Answer:
The molar mass of unknown gas is 145.82 g/mol.
Explanation:
Volume of oxygen gas effused under time t = 8.24 mL
Effusion rate of oxygen gas = 
Molar mass of oxygen gas = 32 g/mol
Volume of unknown gas effused under time t = 3.86 mL
Effusion rate of unknown gas = 
Molar mass of unknown gas = M
Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:




<span>There are a number of ways
to express concentration of a solution. This includes molarity. Molarity is
expressed as the number of moles of solute per volume of the solution.
Calculations are as follows:
Molarity of NO3 ion = 32.0 g Mg(NO3)2 ( 1 mol / 148.3 g ) ( 2 mol NO3 / 1 mol Mg(NO3)2) / .425 L
MOlarity of NO3 ion = 1.02 M </span><span>
</span>
The projectile is the bullet it's self. the chemicals create the explosion to project the bullet