3.01 × 1023 molecules H2O
1 answer:
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Answer:
(a) The normal freezing point of water (J·K−1·mol−1) is
(b) The normal boiling point of water (J·K−1·mol−1) is
(c) the chemical potential of water supercooled to −5.0°C exceed that of ice at that temperature is 109J/mole
Explanation:
Lets calculate
(a) - General equation -
=
=
→ phases
ΔH → enthalpy of transition
T → temperature transition
=
= (
is the enthalpy of fusion of water)
=
(b)
= (
is the enthalpy of vaporization)
=
(c) =
°
°
=
°
°
ΔT
°
°
= 109J/mole