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koban [17]
3 years ago
15

The physical part of digestion is called?

Chemistry
2 answers:
aleksandr82 [10.1K]3 years ago
8 0

Answer:

mechanical digestion is the physical part of digestion

MArishka [77]3 years ago
5 0

Answer:

mechanical digestion

Explanation:

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4.0 mol Na2S reacts with 5.0 mol
Bumek [7]

The number of moles of Na_2SO_4 form from 5.0 moles Na_2S is 5 moles.

<h3>What is a limiting reactant?</h3>

Limiting reactants are those reactants that are completely used up in a chemical reaction.

4.0 mol Na_2S will be completely used since the combining ratio is 1 : 1 : 1.

Na_2S + CuSO_4 ->Na_2SO_4 + CuS

From the chemical equation above, 5.0 moles Na_2S will yield 5 moles of Na_2SO_4.

Learn more about limiting reactants here:

brainly.com/question/14222359

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5 0
2 years ago
Which of the following is true?
Levart [38]
B Eukaryotes are all multicellular
4 0
3 years ago
Read 2 more answers
when chlorine gains an electron to become a chloride ion with a -1 charge it ends up with the electron configuration of argon wh
RUDIKE [14]

Answer:

Only number of electrons of Chlorine and argon are going to be same remaining things like mass,reactivity,ionic radii, and so on will be different so if a chlorine gains a electron we can't call it argon!! chlorine is an diatomic gas, argon exist as monoatomic, chlorine can loose that electron and form bond with another cation in order to remove the charge density,, but argon is stable itself!

3 0
3 years ago
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Sacrificial protection takes place when a magnesium block is
Liula [17]

Answer:

Explained below.

Explanation:

In oil rigs, Sacrificial protection is the protection of the steel against corrosion by using magnesium block which is a more reactive metal. This means that steel which is to be protected from corrosion will be the cathode while magnesium block preventing it from corrosion will be the anode and as such the block will be the one to corrode instead.

The mechanism behind this sacrificial protection is that the steel pipe on the rig will be connected to the magnesium block through copper wires and then the magnesium block will donate its electrons to the steel thereby preventing it from rusting. Thus is a reversible reaction and as such, after the steel Iron undergoes oxidization by receiving electrons from the magnesium block, it will be immediately be reduced to iron as depicted in the equation below.

Mg⇌Mg^(2+) + 2e-

Fe^(2+) + 2e-⇌Fe

6 0
3 years ago
Sodium sulfate dissolves as follows: Na2SO4(s) → 2Na (aq) SO42- (aq). How many moles of Na2SO4 are required to make 1.0 L of sol
never [62]

Answer:

0.05 moles of sodium sulfate are required.

Explanation:

Na_2SO_4(s) \rightarrow 2Na^+ (aq) SO_4^{2-} (aq)

Concentration of sodium ions in 1 L = 0.10 M

0.10 M=\frac{\text{Moles of sodium ions}}{1.0 L}

Moles of sodium ions = 0.10 mol

1 mole of sodium  sulfate gives 2 moles of sodium ions.

Then 0.10 mol of sodium ions will be given by:

\frac{1}{2}\times 0.10 mol=0.05 mol

0.05 moles of sodium sulfate are required.

4 0
3 years ago
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