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3 years ago

9

A structural engineer is using this table to design a wall to protect a city near the ocean. How high should the engineer build

the wall? 50 meters 100 meters 150 meters 200 meters

2 answers:

snow_lady [41]3 years ago

8 0

Answer:

D. 200 meters

Hope this helps!

Explanation:

fredd [130]3 years ago

7 0

Answer: it is D

Explanation: got it wrong so y’all can get it right

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Explan respinsible behaviour inthe computer

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This can be done with Python. If you learn machine learning, you can use python to automate your computers to do things.

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2 years ago

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What is the formula of manganese (Il)<br> phosphate? chemistry related

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The chemical formula of manganese (Il) phosphate is Mn3(PO4)2, which is option 2.

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2 years ago

Iron filings were mixed together with salt crystals. What unique property of iron would be BEST to separate the filings from the

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Iron has magnetic properties, so you would just need to hold a magnet over the mixture and the filings will come right out.

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3 years ago

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Whats the balanced equation for sodium hydroxide + ammonium sulphate=sodium sulphate + amonia + h2o

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Answer:

2NaOH + (NH4) 2SO4 = Na2SO4(s) + 2NH3(g) + 2H2O(l)

Two moles of sodium hydroxide reacts with 1 Mike of ammonium sulphate to give 1 mole of Sodium sulphate, 2 moles of ammonia gas and 2 moles of water

Explanation:

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3 years ago

Tris is a molecule that can be used to prepare buffers for biochemical experiments. It exists in two forms: Tris (a base) and Tr

ale4655 [162]

Solution :

For the reaction :

$\text{TrisH}^+ + H_2O \rightarrow \text{Trish}^- + H_3O^+$

we have

$Ka = \frac{[\text{Tris}^- \times H_3O]}{\text{Tris}^+}$

$=\frac{x^2}{0.02 -x}$

$=8.32 \times 10^{-9}$

Clearing $x$ , we have $x = 1.29 \times 10^{-5} \text{ moles of acid}$

So to reach $\text{pH} = 7.8 (\text{pOH}= 14-7.8=6.2)$ , one must have the $\text{OH}^-$ concentration of the :

$\text{[OH}^-]=10^{-pOH} = 6.31 \times 10^{-7} \text{ moles of base}$

So we can add enough of 1 M NaOH in order to neutralize the acid that is calculated above and also adding the calculated base.

$\text {n NaOH}=1.29 \times 10^{-5}+6.31 \times 10^{-7}$

$= 1.35 \times 10^{-5} \text{ moles}$

Volume NaOH $= 1.35 \times 10^{-5} \text{ moles} \times \frac{1000 \text{ mL}}{1 \text{ mol}} = 0.0135 \text{ mL}$

Tris mass $H^+ = 0.02 \text{ mol} \times 157.6 \text{ g/mol}=3.152 \text{ g}$

Now to prepare the said solution we must mix:

$3.152 \text{ g Tris H} + 0.0135 \text{ mL NaOH} \ 1 M$ gauge to 1000 mL with water.

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3 years ago