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3 years ago

A gas at 65°C occupies 4.0 L. At what temperature will the volume be 3.0 L?

Chemistry

1 answer:

Serjik [45]3 years ago

4 0

Answer:

253.5 K

Explanation:

Charles law equation, which is as follows is used to solve this question:

V1/T1 = V2/T2

Where;

V1 = initial volume (Litres)

V2 = final volume (Litres)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the numerical information provided in this question:

V1 = 4.0 L

V2 = 3.0 L

T1 = 65°C = 65 + 273 = 338K

T2 = ?

Using V1/T1 = V2/T2

V1T2 = V2T1

T2 = V2 × T1/V1

T2 = 3 × 338/4

T2 = 1014/4

T2 = 253.5 K

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Read 2 more answers

How many grams of solute are needed to make 37.5 mL of 0.750 M KI solution? Round to three significant digits.

Marysya12 [62]

4.648 gm of solute is needed to make 37.5 mL of 0.750 M KI solution.

Solution:

We will start with the Molarity

$\text { Molarity }=\text { Mole of solute } \div \text { liter of solution }$

Also we know 1000 ml = 1 L

Therefore 37.5 ml by 1000ml we obtained 0.0375L

Equation for solving mole of solute

$\text { Mole of solute }=\text { Molarity } \times \text { Liters of solution }$

Now, multiply 0.750M by 0.0375

Substitute the known values in the above equation we get

$0.750 \times 0.0375=0.0281$

Also we know that Molar mass of KI is 166 g/mol

So divide the molar mass value to get the no of grams.

$0.028 \times 166=4.648$

So 4.648 gm of Solute is required for make 37.5 mL of 0.750 M KI solution.

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