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Bas_tet [7]
3 years ago
8

Can someone help me write chemical equations of what went wrong in the Chernobyl nucleur accident? Eg. graphite in the rods spee

ding up the reaction, graphite reacting with atomospheric oxygen to cause a second explosion, etc.
Chemistry
1 answer:
zimovet [89]3 years ago
4 0

Answer:

It might be e=FCA

Explanation:

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At 2°C, the vapor pressure of pure water is 23.76 mmHg and that of a certain seawater sample is 23.09 mmHg. Assuming that seawat
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Answer:

0.808  M

Explanation:

Using Raoult's Law

\frac{P_s}{Pi}= x_i

where:

P_s = vapor pressure of sea water( solution) = 23.09 mmHg

P_i = vapor pressure of pure water (solute) = 23.76 mmHg

x_i = mole fraction of water

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\frac{23.09}{23.76}= x_i

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x_2 = 0.0282

x_i = \frac{n_i}{n_i+n_2}  ------ equation (1)

x_2 = \frac{n_2}{n_i+n_2}  ------ equation (2)

where; (n_2) = number of moles of sea water

(n_i) = number of moles of pure water

equating above equation 1 and 2; we have :

\frac{n_2}{n_i}= \frac{0.0282}{0.9178}

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B

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