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Naily [24]
3 years ago
6

A. imagine that you are one of the people who left the luncheon with a contagious disease and interacted with an average of 9 di

fferent people each day. how many people could potentially be infected in 7 days?
b. imagine the other remaining persons who received the contagious disease at the end of the luncheon interacted with an average of 6 different people per day. how many people could potentially be infected in 7 days by these others who left the luncheon?​
Mathematics
1 answer:
shusha [124]3 years ago
8 0

1.       In line with the test each person who came into interaction with the infected person will become infected also. With this information, the calculation would be: 9 people each day for 7days would be equivalent to 9 x 7 which equals 63 people.

2.       Here were 7 other people in the experiment if patient zero is left out. If each person intermingled with 6 different people every day in 7 days then the calculation would be: 7 people infected x 6 new people = 42 infected people each day

42 new people every day x 7 days = 294 infected persons.

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Step-by-step explanation:

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a walking path across a park is represented by the equation y=-2x-7. A new path will be built perpendicular to this path.The pat
jonny [76]

Answer:

The equation that represents the new path is y=(1/2)x-2

Step-by-step explanation:

step 1

Find the slope of the give line

we have

y=-2x-7

so

the slope m is equal to

m=-2

step 2

Find the slope of the perpendicular line to the given line

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal of each other

so

we have

m=-2 -----> slope of the given line

therefore

The slope of the perpendicular line is equal to

m=1/2

step 3

With m=1/2 and the point (-2,-3) find the equation of the line

y-y1=m(x-x1)

substitute

y+3=(1/2)(x+2)

y=(1/2)x+1-3

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8 0
4 years ago
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A cylinder shaped can needs to be constructed to hold 400 cubic centimeters of soup. The material for the sides of the can costs
LenKa [72]

Answer:

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

Step-by-step explanation:

Volume of the Cylinder=400 cm³

Volume of a Cylinder=πr²h

Therefore: πr²h=400

h=\frac{400}{\pi r^2}

Total Surface Area of a Cylinder=2πr²+2πrh

Cost of the materials for the Top and Bottom=0.06 cents per square centimeter

Cost of the materials for the sides=0.03 cents per square centimeter

Cost of the Cylinder=0.06(2πr²)+0.03(2πrh)

C=0.12πr²+0.06πrh

Recall: h=\frac{400}{\pi r^2}

Therefore:

C(r)=0.12\pi r^2+0.06 \pi r(\frac{400}{\pi r^2})

C(r)=0.12\pi r^2+\frac{24}{r}

C(r)=\frac{0.12\pi r^3+24}{r}

The minimum cost occurs when the derivative of the Cost =0.

C^{'}(r)=\frac{6\pi r^3-600}{25r^2}

6\pi r^3-600=0

6\pi r^3=600

\pi r^3=100

r^3=\frac{100}{\pi}

r^3=31.83

r=3.17 cm

Recall that:

h=\frac{400}{\pi r^2}

h=\frac{400}{\pi *3.17^2}

h=12.67cm

The dimensions of the can that will minimize the cost are a Radius of 3.17cm and a Height of 12.67cm.

3 0
3 years ago
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Answer:

3 bags

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4/3 x 9/2 = 36/6

36/6 = 6 square yards

so you will nee 3 bags of soil.

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3 years ago
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