109/8.56=12.7
50+12.7
V=62.7
Mass= Volume x Density so i divided the mass and density to get the volume. and afterwards i would just add it to the mass to get my final answer
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Answer:
the pressure at c = 0.27 atm
Explanation:
Given that:
number of moles (n) = 1.0 moles
Value of gamma in the monoatomic gas (γ) = 5/3
During an isothermal expansion, the volume at b is = 2.5 times the volume at a ; this implies that:

∴ To calculate the pressure at c from a; the process is adiabatic compression; so we apply:

![\frac{P_c}{P_a}=[\frac{V_a}{V_c}]^{(2/3)](https://tex.z-dn.net/?f=%5Cfrac%7BP_c%7D%7BP_a%7D%3D%5B%5Cfrac%7BV_a%7D%7BV_c%7D%5D%5E%7B%282%2F3%29)
![\frac{P_c}{1.0 atm}=[\frac{1}{2.5}]^{(2/3)](https://tex.z-dn.net/?f=%5Cfrac%7BP_c%7D%7B1.0%20atm%7D%3D%5B%5Cfrac%7B1%7D%7B2.5%7D%5D%5E%7B%282%2F3%29)

Thus, the pressure at c = 0.27 atm