If I have 0.725 moles of gas at a temperature of 105 K and a pressure of 3.75 atmospheres the volume of the gas 1.66 litres.
Explanation:
Data given:
number of moles of the gas = 0.725
temperature = 105 K
pressure = 3.75 atm
volume of the gas =?
R = 0.08206 Latm/mole Kelvin
Applying the ideal gas law to calculate the volume of the given gas:
PV = nRT
rearranging the equation to calculate volume:
V = 
putting the values in the equation:
V = 
V = 1.66 Litres.
At a temperature of 105 K and pressure of 3.75 atm, 0.725 moles of gas occupy 1.66 litres of volume.
Answer:
1.67×10^25 molecules
Explanation:
No of molecules = no of moles × Avogadros number
No of moles= mass in gram / molar mass
No of moles of water in given sample = 500.3/18
= 27.79 moles
No of molecules = 27.79× 6.02×10^ 23
= 167.32×10^23 or 1.67×10^25
Lipids are much denser than water so they often " float " on water and also because that lipids and water can not dissolve to form a solution. lipids always tend to remain at top of water since they are denser .
Use Avogadro's number to calculate the number of moles of Mg<span>Cl2 . The number of moles of Cl is twice as </span>much, because the ratio of Cl in MgCl2 to MgCl2 is 2:1. 3.61⋅10246.022⋅10<span>23=5.99. Therefore, there are 12 moles of Cl.</span>