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MrMuchimi
3 years ago
13

A mixture was found to contain 1.05g of SiO2, 0.69g of cellulose and 1.82g of calcium carbonate. What percentage of calcium carb

onate is in the mixture?
Chemistry
2 answers:
mihalych1998 [28]3 years ago
5 0
1,05g+0,69g+1,82g=3,56g\\\\
3,56g \ \ \ \Rightarrow \ \ \ 100\%\\
1,82g \ \ \ \Rightarrow \ \ \ x\\\\
x=\frac{1,82g*100\%}{3,56g}\approx 51,12\%
Ronch [10]3 years ago
3 0

Answer:

51.1 % of the mixture is calcium carbonate

Explanation:

Step 1: Data given

A mixture contains 1.05 grams of SiO2, 0.69 grams of cellulose and 1.82 grams of CaCO3

Step 2: Calculate the total mass of the mixture

Total mass = mass of SiO2 + mass of cellulose + mass of CaCO3

Total mass = 1.05 grams + 0.69 grams + 1.82 grams

Total mass = 3.56 grams

Step 3: Calculate percentage of calcium carbonate is in the mixture

% caCO3 = (mass CaCO3 / mass of mixture) *100%

% CaCO3 = (1.82 grams / 3.56 grams ) * 100%

% CaCO3= 51.1 %

51.1 % of the mixture is calcium carbonate

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maxonik [38]

Answer: The 234.74 grams of sample should be ordered.

Explanation:

Let the gram of  114 Ag to ordered be N_o

The amount required for the beginning of experiment = 0.0575 g

Time requires to ship the sample = 4.2hour = 252 min(1 hr = 60 min)

Half life of the sample ={t_{\frac{1}{2}} = 21 min

\lambda =\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{21 min}=0.033 min^{-1}

\log[N]=\log[N_o]-\frac{\lambda t}{2.303}

\log[0.0575 g]=\log[N_o]-\frac{0.033 min^{-1}\times 252 min}{2.303}

N_o=234.74 grams

The 234.74 grams of sample should be ordered.

4 0
3 years ago
Select the correct answer from each drop-down menu. At chemical equilibrium, the amount of because .
Elena-2011 [213]

Answer:

The answer that completes the question are in BOLD:

At chemical equilibrium, the amount of PRODUCT AND REACTANT REMAIN CONSTANT because the RATES OF THE FORWARD AND REVERSE REACTIONS ARE EQUAL.

Explanation:

In a reversible chemical reaction, an equilibrium is said to be achieved when the rates of the forward reaction is equal to that of the reverse reaction. A reversible reaction is one in which products are formed from reactants simultaneously with the formation of reactants from products.

The combination of two or more substances called REACTANTS gives rise to another substance called PRODUCT, which can in turn give rise to Reactants again. With time, the rate at which the reactants give rise the products, which is called the FORWARD REACTION will be equal to the rate at which the products give rise to the reactants, which is called REVERSE REACTION. At this point, the chemical reaction is said to be in a STATE OF EQUILIBRIUM.

When the rate at which both reaction occurs becomes equal i.e. at an equilibrium state, the concentration of both the reactants and the products becomes constant i.e. no longer changes. Hence, the amount of the reactants forming the products is the same as the amount of products forming the reactants.

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3 years ago
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Answer:

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(B) F⁻, HCOOH

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The hydrogen bonds are formed when the hydrogen is found between two electronegative atoms such as oxygen (O), nitrogen (N) or florine (F).

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3 years ago
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brilliants [131]

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Excited state is the state which represents a high energy state.

An electron in ground state absorbs energy to move to the excited state.



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3 years ago
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