Answer:
We accept H₀ we don´t have enough evidence to support that the mean thickness is greater than 41 mm
Step-by-step explanation:
Sample Information:
Results:
41.8
40.9
42.1
41.2
40.5
41.1
42.6
40.6
From the table we get:
sample mean : x = 41.35
sample standard deviation s = 0.698
Hypothesis Test:
Null Hypothesis H₀ x = 41
Alternative Hypothesis Hₐ x > 41
The test is a one-tail test
If significance level is 0.01 and n = 8 we need to use t-student distribution
From t-table α = 0.01 and degree of freedom df = n - 1 df = 8 - 1
df = 7 t(c) = 2.998
To calculate t(s) = ( x - 41 ) / s/√n
t(s) = ( 41.35 - 41 ) / 0.698/√8
t(s) = 0.35 * 2.83/ 0.698
t(s) = 1.419
Comparing t(s) and t(c)
t(s) < t(c)
t(s) is in the acceptance region we accept H₀
Answer:
y=4(5) =20
Step-by-step explanation:
The answer is 1/2n-4
Multiplying a number n by 1/2 is the same as dividing that number by 2.
Answer: choice A) 7017
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Work Shown:
The first term is a_1 = 24 and we go up by 7 each time.
The common difference is d = 7
The nth term formula we'll use is
a_n = a_1 + (n-1)*d
a_n = 24 + (n-1)*7
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The 1000th term corresponds to n = 1000
Replace every n with 1000
Then use the order of operations (PEMDAS) to simplify
a_n = 24 + (n-1)*7
a_1000 = 24 + (1000-1)*7
a_1000 = 24 + (999)*7
a_1000 = 24 + 6993
a_1000 = 7017
Ok got it. If you have any questions just ask in the chat below :)
