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alekssr [168]
3 years ago
11

When a connector is marked with "al-cu," the connector is suitable for use with copper, copper-clad aluminum, and aluminum condu

ctors?
Chemistry
1 answer:
IgorLugansk [536]3 years ago
6 0

When connectors are marked with a combination of metals, it can be used as a connector of one of the metals or an alloy of the two metals. So in this case, since the marking is “Al – Cu” where Al is aluminium and Cu is copper, therefore the answer is:

<span>Yes, it is suitable for use with copper, copper-clad aluminum, and aluminum conductors.</span>

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Identify each of the following solids as molecular, ionic, or atomic.
Kisachek [45]

Answer :

(A) Br₂ (s) : molecular solids

(B) AgCl (s) : ionic solids

(C) S (s) : atomic solids

(D) CH₄ (s) : molecular solids

Explanation :

Molecular solids : It is defined as the solids in which they are held together by covalent forces, dipole interactions as attractive forces etc.

Ionic solids : It is defined as the solids in which the atoms composed with oppositely charged ions.

Atomic solids : It is defined as the solids in which the molecules are held together by covalent forces and also includes pure substance.

(A) Br₂ (s)

It is molecular solids because they are held together by covalent forces.

(B) AgCl (s)

It is ionic solids because in this atoms composed with oppositely charged ions.

(C) S (s)

It is atomic solids because it is a pure substance.

(D) CH₄ (s)

It is molecular solids because they are held together by covalent forces.

7 0
3 years ago
Calculate the energy of an electron in the n = 2 level of a hydrogen atom.
ANEK [815]

Answer: The energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

Explanation:

Given: n = 2

The relation between energy and n^{th} orbit of an atom is as follows.

E = - \frac{13.6}{n^{2}} eV

Substitute the values into above formula as follows.

E = - \frac{13.6}{n^{2}} eV\\= - \frac{13.6}{(2)^{2}}\\= - 3.40 eV

The negative sign indicates that energy is being released.

Thus, we can conclude that the energy of an electron in the n = 2 level of a hydrogen atom is 3.40 eV.

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Answer:

B

Explanation:

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