1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Maru [420]
3 years ago
7

Write the answer in scientific notation when you multiply 2 x 104 by 3 x 104.

Chemistry
1 answer:
emmasim [6.3K]3 years ago
7 0

Answer:

6× 10⁸

Explanation:

We need to find the multiplication of 2 x 10⁴ by 3 x 10⁴.

2 x 10⁴ × 3 x 10⁴

= (3 × 2) x 10⁴ x 10⁴

= 6 x 10⁴ x 10⁴

= 6 × 10⁴⁺⁴

= 6× 10⁸

Hence, the required answer is 6× 10⁸.

You might be interested in
A block of metal has a volume of 14.0in3 and weighs 5.26lb .
natulia [17]
Mass of block, m = 5.26 lb  
1 lb = 453.592 g
 5.26 lb = 2385.896 g
V = 14 in3
 1 in = 2.5 cm
 1 in3 = 15.625 cm3
 14 in3 = 218.75 cm3


Density = mass/volume
 = 2358.896 / 218.75
 = 10.783 g/cm3
6 0
3 years ago
Read 2 more answers
Laws differ from theories because laws do not provide
o-na [289]

Answer:

C. An explanation

7 0
3 years ago
- How many grams are in 4.6 x 1016 molecules of phosphorus trichloride (PCI)?
MariettaO [177]

Answer:

0.0000101 grams.

Explanation:

First of all, use Avogadro's number to convert from molecules to moles.

Avogadro's number is 6.02 x 10^23.

Second of all, to convert from moles to grams, find the substance formula of phosphorus trichloride. After finding the substance formula, then find the molar mass of phosphorus trichloride.

Phosphorus trichloride is PCl3

Now find the molar mass of PCl3

P = 31.0 amu

Cl = 35.5 amu

They are three chlorine atoms and one phosphorus atom. So you do this.

31.0(1) + 35.5(3) = 137.5 g/mol

Now use dimensional analysis to show your work

4.6 x 10^16 grams of PCl3 * 1 mol/ 6.02 x 10^23 * 137.5 g/mol / 1 mol

The grams and the moles cancel out.

So now do [(4.6 x 10^16) / (6.02 x 10^23)] x 137.5

and you will get 0.000010507

4.6 has the fewest digits which is 2.

So use sig figs and the answer rounds to the nearest millionths.

0.000010507 rounds to 0.0000101

So the final answer is 0.0000101 grams(don't forget the units)

Hope it helped!

4 0
3 years ago
The stars are H and the circles are O by the way
shepuryov [24]

Answer:2 is correct

Explanation:

6 0
3 years ago
The volume of the aquarium in our classroom is 1890 L. The density of seawater is 1.03g/cm^3. What is the mass of the water in o
guapka [62]
Density can be calculated using the following rule:
density = mass / volume
therefore,
mass = density x volume
From the givens:
we have the density = 1030 kg/m^3 and volume = 1.89 m^3

Substitute in the equation to get the mass as follows:
mass = 1030 x 1.89 = 1.9467 x 10^3 kg
5 0
3 years ago
Other questions:
  • Charles’ Law can be expressed mathematically as V=kT. If the constant k for 6.0 L of gas is 0.020 L/K (liters per kelvin), what
    5·1 answer
  • What is the meaning of sulfur in biology ​
    5·2 answers
  • Three carbon atoms are linked by single covalent bonds such that they form the shape of a V. All of the unshared electrons form
    12·1 answer
  • What is the mass of 2.70 ×10^22 molecules of NaOH (Molar mass = 40.0 g/mol)?
    6·1 answer
  • How many moles of copper are needed to react with sulfur to produce 0.25 moles of copper sulfide
    7·2 answers
  • Julie finds a snail on the sidewalk and wants to know whether or not the snail moves throughout the day. She places a single mar
    10·2 answers
  • Determine the number of miles of C in each sample​
    15·1 answer
  • Hi, can someone help me balance this chemistry equation:<br> H2SO4 + RbOH -&gt; Rb2SO4 + H2O
    8·1 answer
  • A researcher selects three regions X, Y, and Z, and records the types of discharge that enter the regions’ rivers.
    10·1 answer
  • Describe the difference between polar covalent bonds and nonpolar covalent bonds using these two molecules - H2 and HCl. Which m
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!