<u>Answer:</u> The mass of water that should be added in 203.07 grams
<u>Explanation:</u>
To calculate the molality of solution, we use the equation:
![\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}](https://tex.z-dn.net/?f=%5Ctext%7BMolality%7D%3D%5Cfrac%7Bm_%7Bsolute%7D%5Ctimes%201000%7D%7BM_%7Bsolute%7D%5Ctimes%20W_%7Bsolvent%7D%5Ctext%7B%20%28in%20grams%29%7D%7D)
Where,
m = molality of barium iodide solution = 0.175 m
= Given mass of solute (barium iodide) = 13.9 g
= Molar mass of solute (barium iodide) = 391.14 g/mol
= Mass of solvent (water) = ? g
Putting values in above equation, we get:
![0.175=\frac{13.9\times 1000}{391.14\times W_{solvent}}\\\\W_{solvent}=\frac{13.9\times 1000}{391.14\times 0.175}=203.07g](https://tex.z-dn.net/?f=0.175%3D%5Cfrac%7B13.9%5Ctimes%201000%7D%7B391.14%5Ctimes%20W_%7Bsolvent%7D%7D%5C%5C%5C%5CW_%7Bsolvent%7D%3D%5Cfrac%7B13.9%5Ctimes%201000%7D%7B391.14%5Ctimes%200.175%7D%3D203.07g)
Hence, the mass of water that should be added in 203.07 grams
Answer:It is C i got it correct
Explanation:
Answer:
The electron cloud
Explanation:
<em>Rutherford’s gold foil experiment</em> showed that the atom consisted of a tiny nucleus inside of a much larger electron cloud.
The diameter of the electron cloud is about 50 000 times that of the nucleus.
There are different kinds of reactions. To name some, these are the synthesis reaction, decomposition reaction, single-replacement reaction, double-replacement reaction, combustion reaction, redox reaction, etc. For this type of reaction involving two reactants to yield only one product, <em>this is a synthesis reaction.</em>
<em>P₄ (s) + 6 Ca (s) --> 2 Ca₃P₂ (s)</em>