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zalisa [80]
3 years ago
5

Calculate the specific heat of the substance if 373 J is required to raise the temperature of a 312 gram sample by 25°C?

Chemistry
1 answer:
I am Lyosha [343]3 years ago
4 0

Explanation:

Q = 373J

∆∅ = 25°C

m = 312g

c = x

Q = mc∆∅

373 = 312(x)(25)

373 = 7800x

x = 373/7800

x = 0.0478J/(g°C)

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