I'm NOT 100% confident in my answers.
Graph 1:
Range: Option B
Graph 2:
Range: Option A
The range has to start at zero since that's the lowest point we can go, only one with zero is first option.
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Answer:
Step-by-step explanation:
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The descriptions of the transformations are:
- Vertex: (-6, 0)
- Stretch factor: 2
- Domain: set of all real numbers
- Range: set of real numbers greater than or equal to 0
<h3>How to describe transformations, graph, and state domain & range using any notation?</h3>
The function is given as:
f(x) = -2|x + 6|
The above function is an absolute value function, and an absolute value function is represented as:
f(x) = a|x - h| + k
Where
Vertex = (h, k)
Scale factor = a
So, we have:
a = -2
(h, k) = (-6, 0)
There is no restriction to the input values.
So, the domain is the set of all real numbers
The y value in (h, k) = (-6, 0) is 0
i.e.
y = 0
Because the factor is negative (-2), then the vertex is a minimum
So, the range is all set of real numbers greater than or equal to 0
Hence, the descriptions of the transformations are:
- Vertex: (-6, 0)
- Stretch factor: 2
- Domain: set of all real numbers
- Range: set of real numbers greater than or equal to 0
Read more about absolute value function at
brainly.com/question/3381225
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Hey!
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We Know:
m∠AED = 34°
m∠EAD = 112°
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Solution:
You notice 4 small triangles in both triangles. That shows that both triangles are the same.
The angles are the same for m∠BDC and m∠AED.
The angles are the same for m∠ADB and m∠EAD
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Angles:
m∠BDC = 34°
m∠ADB = 112°
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Congruent Angles:
m∠AED ≡ m∠BDC
m∠EAD ≡ m∠ADB
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Hope This Helped! Good Luck!
Answer:
16 m × 11 m
Step-by-step explanation:
The dimension of the gym is 20 m x 15 m. An outbound of 2m width is to be cut out from the gym to form the basketball court.
The original length of gym = 20 m and original width of gym = 15 m
2 m would be cut at both sides of the gym length for the outbound. Also 2 m would be cut at both sides of the gym width for the outbound. Therefore:
Length of basketball court = 20 m - (2 * 2m) = 20 m - 4 m = 16 m
Width of basketball court = 15 m - (2 * 2m) = 15 m - 4 m = 11 m
Therefore the dimensions of the basketball court is:
16 m × 11 m
