-3(5 + 8x) - 20 ≤ -11 |use distributive property: a(b + c) = ab + ac

-15 - 24x - 20 ≤ -11

-35 - 24x ≤ -11 |add 35 to both sides

-24x ≤ 24 |change signs

24x ≥ -24 |divide both sides by 24

x ≥ -1

3 0

3 years ago

Simplify: (−2a2b) • (4a5b2) −8a7b3 −8a10b2 −8(ab)10 16a7b3

7nadin3 [17]

I hope this helps you

-2a^2b.4.a^5.b^2

-8.(a^2+5)(b^1+2)

-8.a^7.b^3

7 0

3 years ago

Read 2 more answers

A newspaper editor starts a retirement savings plan in which $225 per month is deposited at the beginning of each month into an

qwelly [4]

Answer: the value of this investment after 20 years is $112295.2

Step-by-step explanation:

We would apply the formula for determining future value involving deposits at constant intervals. It is expressed as

S = R[{(1 + r)^n - 1)}/r][1 + r]

Where

S represents the future value of the investment.

R represents the regular payments made(could be weekly, monthly)

r = represents interest rate/number of interval payments.

n represents the total number of payments made.

From the information given,

Since there are 12 months in a year, then

r = 0.066/12 = 0.0055

n = 12 × 20 = 240

R = $225

Therefore,

S = 225[{(1 + 0.0055)^240 - 1)}/0.0055][1 + 0.0055]

S = 225[{(1.0055)^240 - 1)}/0.0055][1.0055]

S = 225[{(3.73 - 1)}/0.0055][1.0055]

S = 225[{(2.73)}/0.0055][1.0055]

S = 225[496.36][1.0055]

S = $112295.2

7 0

3 years ago

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species

kotegsom [21]

Answer:

$P(t) = \frac{160000e^{1.36t}}{2000 + 80(e^{1.36t} - 1)}$

Step-by-step explanation:

The logistic equation is the following one:

$P(t) = \frac{KP(0)e^{rt}}{K + P(0)(e^{rt} - 1)}$

In which P(t) is the size of the population after t years, K is the carrying capacity of the population, r is the decimal growth rate of the population and P(0) is the initial population of the lake.

In this problem, we have that:

Biologists stocked a lake with 80 fish and estimated the carrying capacity (the maximal population for the fish of that species in that lake) to be 2,000. This means that $P(0) = 80, K = 2000$ .