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3 years ago

The astronaut climbed up the (blank) of the moon.

Chemistry

2 answers:

madreJ [45]3 years ago

8 0

The answer is C. terrae according to NASA.com

castortr0y [4]3 years ago

5 0

The answer is C
hope this helpe u out!!!!!!!

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How many milliliters of water are needed to prepare a 3.5M solution of NaOH if you have .5mol of the solute

Mamont248 [21]

Answer:

1335.12 mL of H2O

Explanation:

To calculate the mililiters of water that the solution needs, it is necessary to know that the volume of the solution is equal to the volume of the solute (NaOH) plus the volume of the solvent (H2O).

From the molarity formula we can first calculate the volume of the solution:

$M=\frac{solute moles}{solution volume}$

$Solutionvolume=\frac{solute moles}{M} =\frac{5mol}{3.5\frac{mol}{L} } =1.429L$

The volume of the solution as we said previously is:

Solution volume = solute volume + solvent volume

To determine the volume of the solute we first obtain the grams of NaOH through the molecular weight formula:

$MW=\frac{mass}{mol}$

$Mass=MW*mol=39.997\frac{g}{mol} *5mol=199.985g$

Now with the density of NaOH the milliliters of solute can be determined:

$d=\frac{mass}{volume}$

$Volume=\frac{mass}{d} =\frac{199.985g}{2.13\frac{g}{mL} } =93.88mL of NaOH$

Having the volume of the solution and the volume of the solute, the volume of the solvent H2O can be calculated:

Solvent volume = solution volume - solute volume

Solvent volume = 1429 mL - 93.88 mL = 1335.12 mL of H2O

7 0

3 years ago

In a desert, soil containing a mixture of sand and small rocks is exposed to wind erosion. Over time, how would the land surface

amid [387]

Sand dunes would be created due to the mixture falling on each other
x

3 0

3 years ago

Read 2 more answers

How many moles of CCI are there in 78.2 g of CCI.?

vaieri [72.5K]

Answer:

0.508 mole

Explanation:

NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.

The number of mole present in 78.2 g of CCl₄ can be obtained as follow:

Mass of CCl₄ = 78.2 g

Molar mass of CCl₄ = 12 + (35.5×4)

= 12 + 142

= 154 g/mol

Mole of CCl₄ =?

Mole = mass / molar mass

Mole of CCl₄ = 78.2 / 154

Mole of CCl₄ = 0.508 mole

Therefore, 0.508 mole is present in 78.2 g of CCl₄

6 0

3 years ago

What is the concentration of a 500 mL solution with 25 mol of HF? Write your answer with TWO decimal places and round accordingl

statuscvo [17]

Answer:

Explanation:

3 0

3 years ago

Is anyone online 2 help,Sodium is a reactive metal.Why nd don't spam brainlest and thx is waiting answer it ❤️

morpeh [17]

It is because sodium is one of the most reactive metals.

There is a reaction would take place between magnesium and sodium chloride.

The chemical reaction between these two metals is given below.

It is Mg + 2NaCl >> MgCl2. + 2Na.

The symbol of this chemical element is Na.

It has the atomic number of eleven

Hope this helps *smiles*

6 0

3 years ago