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Vlad [161]
2 years ago
9

Tyler paid $16 for 4 raffle tickets. What is the price per ticket?

Mathematics
2 answers:
Mekhanik [1.2K]2 years ago
5 0

Answer:

$4

Step-by-step explanation:

16 divide by 4 equals 4

slamgirl [31]2 years ago
4 0

Answer:

$4 per raffle ticket

Step-by-step explanation:

I would make a proportion:

?= price per ticket

4 - $16

1  - ?

Solve: 1×16÷4= 4

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Q.13 is no solution since the y intercept of the 2 equation differ but gradient is the same therefore if you were to draw a graph there wont be any intersection between the equations

the next question's answer is no solution
6 0
3 years ago
Read 2 more answers
(e) 3x2 + 10x + 3 by x + 3<br>​
kap26 [50]

Answer:

(3x+1)(x+3) is the factorised form for the expression.

Step-by-step explanation:

:3

x

2

+

10

x

+

3

We can Split the Middle Term of this expression to factorise it.

In this technique, if we have to factorise an expression like  

a

x

2

+

b

x

+

c

, we need to think of 2 numbers such that:

N

1

⋅

N

2

=

a

⋅

c

=

3

⋅

3

=

9

and,

N

1

+

N

2

=

b

=

10

After trying out a few numbers we get:

N

1

=

9

and  

N

2

=

1

9

⋅

1

=

9

, and  

9

+

(

1

)

=

10

3

x

2

+

10

x

+

3

=

3

x

2

+

9

x

+

1

x

+

3

=

3

x

(

x

+

3

)

+

1

(

x

+

3

)

(

3

x

+

1

)

(

x

+

3

)

is the factorised form for the expression.

is the factorised form for the expression.

8 0
3 years ago
I need help on this math problem!
swat32

(-7, 2) is the location of W.

because W on the X axis is -7

and W on the Y axis is 2.

making it (-7, 2)

8 0
3 years ago
According to a census performed in a certain country in a particular year, about 209,280,000 of it's residents were adults, and
gayaneshka [121]
54160000/209280000

= 0.2587
=25.88%
7 0
3 years ago
1.find the sum. (3^3+5x^2+3x-7)+(8x-6x^2+6)<br> 2. Find the Difference: (8x-4x^2+3\)-(x^3+7x^2+3x-8)
vlada-n [284]

1.

(3^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=27\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=-x^2+11x+26

or if you mean (3x^3+5x^2+3x-7)+(8x-6x^2+6):

(3x^3+5x^2+3x-7)+(8x-6x^2+6)=\\\\=3x^3\ \underline{+\,5x^2}\ \underline{ \underline{+\,3x}}-7\ \underline{\underline{\,+8x}}\ \underline{-\,6x^2}+6=\\\\=3x^3-x^2+11x-1

2.

(8x-4x^2+3)-(x^3+7x^2+3x-8)=\\\\=\underline{8x}\ \underline{\underline{-\ 4x^2}}+3-x^3\ \underline{\underline{-\,7x^2}}\ \underline{-\,3x}+8=\\\\=-x^3-11x^2+5x+10

3 0
3 years ago
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