Answer:
(23.97, 24.03)
Step-by-step explanation:
Given the data:
224.120 224.001 224.017 223.982 223.989 223.961 223.960 224.089 223.987 223.976 223.902 223.980 224.098 224.057 223.913 223.999
Confidence interval = m ± Zcritical(s/√n)
n = sample size = 16
Zcritical at 95% = 1.96
Using calculator :
Sample mean, m = 224.0019
Standard deviation, s = 0.0618
Lower bound : 24.0019 - 1.96(0.0618/√16) = 23.971618
Upper bound : 24.0019 + 1.96(0.0618/√16) = 24.032182
(23.97, 24.03)
We can solve this question in 2 ways: either using
degrees or converting the degrees into
radians.
Since, the question says degrees itself and there is no specification of using radians only, so I have solved it using degrees itself.
Part (a):
Perimeter of sector ORS = 2*Radius + Arc RS = 2*21 +
Part (b):
Area of sector ORS =
Area of sector POQ =
Thus, area of shaded region
= Area of sector ORS - Area of sector POQ
=
Answer: 15 ; (g^5) - h
Step-by-step explanation:
- To find 15% of 100, multiply 100 and 15/100. The 100's get crossed out and the answer is 15.
- The expression is (g^5) - h.
Each week, a cook purchased 12 LBS. of Butter:
During the Last year: (12 Months):
Cook Paid:
Little: $23.04
Much: $29.40, For Butter he or she purchased in a week:
Question: is: what is the Difference between, the Greatest price per pound, and the least price per pound of butter the cook paid within the last year?
EQUATION:
Least Paid / 12 =====> 23.04 /12
Most Paid / 12 ======> 29.40 / 12
Divide:
23.04 / 12 = 1.92 / LB
29.40 / 12 = 2.45 / LB
Now Subtract:
2.45 - 1.92
Answer ======> 0.53 is the difference, between the greatest price per round, and least price per round of butter the cook would have paid within the last year.
Hope that helps!!! : )
Answer:
7 goldfish
Step-by-step explanation:
10-3=7
