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tino4ka555 [31]
3 years ago
11

Need help with this!

Mathematics
1 answer:
Damm [24]3 years ago
4 0

Answer:

The sum of the interior angles of any triangle = 180°

Step-by-step explanation:

(15x + 1) + (6x + 5) + (4x – 1) = 180°

25x + 5 = 180

25x = 175

x = 7

Evaluate x into each: m<A = 106° , m<B = 47° , m<C= 27°

106 + 47 + 27 = 180

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1
sleet_krkn [62]

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}

From Left side:

\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)

\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}

NOTE: sin²θ + cos²θ = 1

\dfrac{1 + 2cos\theta sin\theta}{sin^2\theta-cos^2\theta}+\dfrac{1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{1 + 2cos\theta sin\theta+1-2cos\theta sin\theta}{sin^2\theta-cos^2\theta}

\dfrac{2}{sin^2\theta-cos^2\theta}

\dfrac{2}{\bigg(sin^2\theta-cos^2\theta\bigg)\bigg(\dfrac{cos^2\theta}{cos^2\theta}\bigg)}

\dfrac{2sec^2\theta}{\dfrac{sin^2\theta}{cos^2\theta}-\dfrac{cos^2\theta}{cos^2\theta}}

\dfrac{2sec^2\theta}{tan^2\theta-1}

Left side = Right side <em>so proof is complete</em>

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3 years ago
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4 years ago
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What is the value of x will make the inequality true. 5x - 10 &lt; 75?
Ipatiy [6.2K]

Answer:

x=16 or any value less than 16.

Step-by-step explanation:

16x5=80 and subtract 10 you get 70. X has to equal a value that makes the whole left side of the equation "smaller" than the irght side, and 16 or any value less than that would accomplsish this.

5 0
3 years ago
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For geometry:(<br><br> i’ll give a brainist!!!
kvasek [131]
<h3>Answer: Angle Q = 133 degrees</h3>

========================================================

Work Shown:

Recall that for any triangle, the three angles always add to 180

P+Q+R = 180

(x+13) + (10x+13) + (2x-2) = 180

(x+10x+2x) + (13+13-2) = 180

13x+24 = 180

13x = 180-24

13x = 156

x = 156/13

x = 12

Now that we know x, we can find the angle measures

  • angle P = x+13 = 12+13 = 25 degrees
  • angle Q = 10x+13 = 10*12+13 = 120+13 = 133 degrees
  • angle R = 2x-2 = 2*12-2 = 24-2 = 22 degrees

As a way to check if we have the right answer or not, we see that,

P+Q+R = 25+133+22 = 180

So the answer is confirmed.

4 0
3 years ago
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