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asambeis [7]
3 years ago
14

Can somebody help me plz and thank you

Mathematics
1 answer:
WITCHER [35]3 years ago
4 0

Answer:

sure, what do you need help with?

Step-by-step explanation:

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Consider the following data set:
Komok [63]

Answer:

+5 Range; The range is now 25

Step-by-step explanation:

The original range would be calculated by subtracting 20 from 40, giving you 20 as the range. However, with the point 15 added, there would be a new lowest number, making the new range be 40-15, which is 25.

3 0
3 years ago
What is the annual share of the profit awarded to the owner of a share of stock called?
madam [21]
I think its common stock
5 0
3 years ago
I need help please.
inn [45]
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
6.008 can be written as =

▪️6008 / 100
▪️6008 / 100
= 3004 / 50
= 1502 / 25
= 1502 / 25 in mixed fraction .
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
That’s it...
7 0
3 years ago
Hey guys whats the better deal 56/25 or 32.05/15
Ray Of Light [21]

56/25 = 2.24

32.05/15= 2.13666..


If you're looking for a larger value 56/25 is your answer.

7 0
3 years ago
Need help please !!!!!!
11Alexandr11 [23.1K]
A perfect square must be hidden within all of those radicands in order to simplify them down to what the answer is.  \sqrt{192}= \sqrt{64*3}= 8\sqrt{3}.  \sqrt{80}= \sqrt{16*5}=4 \sqrt{5}.  \sqrt{12288}= \sqrt{4096*3}=64 \sqrt{3}.  The rules for adding radicals is that the index has to be the same (all of our indexes are 2 since we have square roots), and the radicands have to be the same.  In other words, we cannot add the square root of 4 to the square root of 5.  They either both have to be 4 or they both have to be 5.  So here's what we have thus far: 8 \sqrt{3}+4 \sqrt{5}+64 \sqrt{3}.  We can add 8 \sqrt{3} and 64 \sqrt{3} to get 72 \sqrt{3}.  That means as far as our answer goes, A = 72 and B = 4, or (72, 4), choice a.
5 0
3 years ago
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