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gtnhenbr [62]
3 years ago
7

I need to know how to do the answer and why that’s the anwer

Mathematics
1 answer:
Pavel [41]3 years ago
6 0
Ok so the answer is
4 {x}^{2}

so we multiply numbers that have the same variable

2 {x}^{3} \: \: \times {2x}^{ - 1} \\ \\
multiply 2 x 2

2 \times 2 = 4
then multiply the exponents

x ^{3} \times x ^{ - 1}
multipling like this will look like addition.
{x}^{3} \times {x}^{ - 1} = {x}^{2}
so in other words you could do it like this too
{x}^{3} + {x}^{ - 1} = {x}^{2}
now add the exponent with 4
4 + {x}^{2} = 4x ^{2}

now for the last part
{y}^{3} + {y}^{ - 3} = 0
because -3 and 3 added together make 0
0 + 4 {x}^{2} = 4 {x}^{2}
I hope this help(it looks complicated but it's very easy and I hope I helped you out)
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frez [133]

Answer:

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<em>If what you wrote is what you intend</em>, then the equation simplifies to 4x^2 -16 = 0.

Dividing by 4 and factoring the difference of squares gives ...

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