Answer:
d= 10.44030651
Step-by-step explanation:
The diameter is the length between the endpoints. We can find it using the distance formula.
d= sqrt((x2-x1)^2+(y2-y1)^2 )
d = sqrt((-6-4)^2+ (-1-2)^2)
d = sqrt((-10)^2+(-3)^2)
d= sqrt(100+9)
d = sqrt(109)
d= 10.44030651
<span>B. The sample might not be representative of the population because it only includes students who are attending an after-school activity.</span>
Answer:
B
Step-by-step explanation:
Start by breaking down the equation
-1/2 x 10 = -5
-1/2x1/4=-1/4
Then combine your answer
-5=1/8
Answer:
The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.
Step-by-step explanation:
The volume (
), in cubic centimeters, and surface area (
), in square centimeters, formulas for the candle are described below:
(1)
(2)
Where:
- Radius, in centimeters.
- Height, in centimeters.
By (1) we have an expression of the height in terms of the volume and the radius of the candle:

By substitution in (2) we get the following formula:


Then, we derive the formulas for the First and Second Derivative Tests:
First Derivative Test



![r = \sqrt[3]{\frac{V}{2\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BV%7D%7B2%5Cpi%7D%20%7D)
There is just one result, since volume is a positive variable.
Second Derivative Test

If
:

(which means that the critical value leads to a minimum)
If we know that
, then the dimensions for the minimum amount of plastic are:
![r = \sqrt[3]{\frac{V}{2\pi} }](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7BV%7D%7B2%5Cpi%7D%20%7D)
![r = \sqrt[3]{\frac{3217\,cm^{3}}{2\pi}}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B3%5D%7B%5Cfrac%7B3217%5C%2Ccm%5E%7B3%7D%7D%7B2%5Cpi%7D%7D)




And the amount of plastic needed to cover the outside of the candle for packaging is:



The candle has a radius of 8 centimeters and 16 centimeters and uses an amount of approximately 1206.372 square centimeters.
Hello!
0.3 × 0.03 = 0.009
The mass of the flower is 0.009 kilogram.