1.) 40, 2.) 8, 3.) 18, 4.) 15, 8.) 12, 9.) 30, 10.) 72, 11.) 36
<span>#include <iostream>
using namespace std;
class InventoryTag {
public:
InventoryTag();
int getQuantityRemaining() const;
void addInventory(int numItems);
private:
int quantityRemaining;
};
InventoryTag::InventoryTag() {
quantityRemaining = 0;
}
int InventoryTag::getQuantityRemaining() const {
return quantityRemaining;
}
void InventoryTag::addInventory(int numItems) {
if (numItems > 10) {
quantityRemaining = quantityRemaining + numItems;
}
}
int main() {
InventoryTag redSweater;
int sweaterShipment = 0;
int sweaterInventoryBefore = 0;
sweaterInventoryBefore = redSweater.getQuantityRemaining();
sweaterShipment = 25;
cout << "Beginning tests." << endl;
// FIXME add unit test for addInventory
/* Your solution goes here */
cout << "Tests complete." << endl;
return 0;
}</span>
5-3/-4-2=-2/6 the slope of the line is -2/6. This is the case because you do y1-y2 over x1-x2. ANSWER -2/6
Answer:
<em>summation of five times negative three to the power of n from n equals zero to infinity</em>
Step-by-step explanation:
<u>Summation Notation
</u>
It represents the sum of a finite or infinite number of terms. Let's analyze the terms of the given succession:
5-15+45-135+...
If we take 5 as a common factor, we have
5(1-3+9-27+...)
The parentheses contain the alternate sum/subtraction of powers of 3. The odd terms are positive, the even terms are negative, thus the exponent must be n starting from 0 or n-1 starting from 1
The summation is then represented by
This corresponds with the option:
<u>summation of five times negative three to the power of n from n equals zero to infinity</u>
Answer: I believe that it might be $1.00
Step-by-step explanation: Well the problem doesn’t tell you how much money he HAD, so if you do 1/3+4/6 you should get 6/6 or 1 as the amount that Lane had.
