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ryzh [129]
3 years ago
10

What is an element that needs to lose or gain 4 valence electrons in order to become stable?

Physics
1 answer:
tiny-mole [99]3 years ago
4 0

Answer:

Elements in Group 14 could lose four, or gain four electrons to achieve a noble gas structure. In fact, if they are going to form ions, Group 14 elements form positive ions. Carbon and silicon form covalent bonds. Carbon's millions of organic compounds are all based on shared electrons in covalent bonds.

Explanation:

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You normally drive a 12-h trip at an average speed of 100 km/h . Today you are in a hurry. During the first two-thirds of the di
kherson [118]

Answer:

78 km/h

Explanation:

If I normally drive a 12 hour trip at an average speed of 100 km/h, my destination has a total distance of:

  • 100 km/h · 12 h = 1,200 km

Today, I drive the first 2/3 of the distance at 116 km/h. Let's first calculate what 2/3 of the normal distance is.

  • 1,200 * 2/3 = 800 km

I've driven 800 km already. I need to drive 400 km more to reach my final destination. I need to figure out my average speed during this last 1/3 of the distance.

To do this, I first need to calculate how much time I spent driving 116 km/h for the past 800 km.

  • 116 km/1 h = 800 km/? h
  • 800 = 116 · ?
  • ? = 800/116
  • ? = 6.89655172

I spent 6.89655172 hours driving during the first 2/3 of the distance.

Now, I need to subtract this value from 12 hours to find the remaining time I have left.

  • 12 h - 6.89655172 h = 5.10344828 h  

Using this remaining time and my remaining distance, I can calculate my average speed.

  • ? km/1 hr = 400 km/5.10344828 h
  • 5.10344828 · ? = 400
  • ? = 400/5.10344828
  • ? = 78.3783783148  

My average speed during the last third of the distance is around 78 km/h.

8 0
2 years ago
A car is driving 25.5 m/s when it hits
IceJOKER [234]

Answer:

it takes the car 4.362 seconds to cover the distance of 88.4 m.

Explanation:

The distance the car covers is given by the function

x(t) = vt-\dfrac{1}{2}at^2,

where v = 25.5m/s , and a = 2.40m/s, putting  these in we get:

x(t) = 25.5t-\dfrac{1}{2}(2.4)t^2\\\\x(t) = 25.5t-1.2t^2

Now, when the car has moved to 88.4m, x(t) = 88.4 , or

x(t) = 25.5t-1.2t^2 = 88.4

which is a quadratic equation with solutions

t = 4.362s,\\t = 16.887s

We take the first solution t = 4.362s, <em>since at that time the car is still moving right and decelerating</em>. The second solution t =16.887 describes the situation where the car has stopped decelerating and is now moving leftwards because the decelerating is leftwards, <em>which is utterly wrong because we know that cars do not start moving backwards after the brakes have stopped them! </em>

Thus, it takes the car 4.362 seconds to cover the distance of 88.4 m.

6 0
3 years ago
What can be found by counting the number of troughs per second in a wave diagram
zysi [14]
Frequency,................
4 0
3 years ago
Read 2 more answers
Which two quantities can be used to describe motion? A: Displacement and weight. B: speed and acceleration. C: speed and mass. D
HACTEHA [7]
The answer is B as all the other options contain quantities not related to describing motion
3 0
2 years ago
Two students are balancing on a 10m seesaw. The seesaw is designed so that each side of the seesaw is 5m long. The student on th
monitta

Answer:

x = 4 m

Explanation:

For this exercise we must use the rotational equilibrium relationship, where we place zero at the turning point and counterclockwise rotations we will consider positive

as it indicates that the bar is in equilibrium, its center of mass coincides with the turning point, so the distance is zero and does not create torque on the system

        ∑τ  = 0

        W 3 - w x = 0

        x = 3W / w

        x = 3 Mg / mg

        x = 3 M / m

let's calculate

       x = 3 60/45

       x = 4 m

7 0
2 years ago
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