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Fudgin [204]
3 years ago
10

Compare the percent change in angular momentum of the system to the percent change in the rotational kinetic energy of the syste

m. Explain the difference between these two values.
Physics
1 answer:
Lapatulllka [165]3 years ago
8 0

Answer:

change in the angular momentum gives a greater change in the kinetic energy since it has a quadratic dependence with the angular velocity

Explanation:

Let's write the definition of angular momentum

         L = I w

the kinetic energy is

         K = ½ I w²

         

         w = L / I

we substitute

       K = ½ I L² / I²

       K = L² / 2I

      K / L = w / 2

     

therefore a change in the angular momentum gives a greater change in the kinetic energy since it has a quadratic dependence with the angular velocity

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A golf club with mass 0.5 kg is swung at 23 m/s toward a stationary golf ball on a tee. The club barely slows down to 17 m/s, bu
mylen [45]

Answer:

I gotchu fam. 0.0435 kg

Explanation:

m1v1+m2v2=m1v1f+m2v2f

(0.5)(23)+(m2)(0)=(0.5)(17)+(m2)(69)

11.5=8.5+69m2

3=69m2

0.0435 kg

5 0
3 years ago
Every day a certain amount of water evaporates from Earth’s oceans, lakes, and land surface and forms water vapor and clouds in
pochemuha

Answer:

0.0000000010 joules

Explanation:

Amount : 1540.3 nanojoules (nJ)

Equals : 0.0 joules (J)

8 0
3 years ago
If Steve throws the football 50 meters in 3 seconds, what is the average speed of the football? Speed = distance / time Question
leva [86]

Answer:

A. 16.67 m/s

Explanation:

Speed or velocity refers to the rate of change in distance over a change in time. That is;

Speed = Distance ÷ time

Where;

Speed is in metre/seconds

Distance is in metre

Time is in seconds.

In this question, Steve throws a football 50 meters in 3 seconds. The average speed can be calculated this:

S = D/t

Where; d = 50m, t = 3s

S = 50/3

S = 16.6666666

S = 16.67m/s

5 0
3 years ago
(b) Fig. 1.1 shows two airports A and C. north SE с sea land क WE not to scale Fig. 1.1 An aircraft flies due north from A for a
GalinKa [24]

The addition of vectors and the uniform motion allows to find the answers for the questions about distance and time are:

  • The distance to go between airports A and C  is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Vectors are quantities that have modulus and direction, so their addition must be done using vector algebra.

In this case the plane flies towards the North a distance of y = 360 10³ m at an average speed of v = 170 m / s, when arriving at airport B it turns towards the East and travels from x = 100 10³ m, until' it the distance reaches the airport C

Let's use the Pythagoras theorem to find the distance traveled

               R = Ra x² + y²

               R =   10³

               R = 373.6 10³ m

They indicate the average speed for which we can use the uniform motion ratio

               v = \frac{\Delta y }{t}

                t = \frac{\Delta y}{v}

They ask for the time in in from airport A to B, we calculate

                t = 360 10 ^ 3/170

                t = 2.117 10³ s

In conclusion we use the addition of vectors the uniform motion we can find the answer for the question of distance and time are:

  • The distance to go between airports A and C B is 373.6 10³ m
  • The time to go from airport A to B is 2117 s

Learn more here: brainly.com/question/15074838

5 0
3 years ago
A 4.0 kg mass is attached to a spring whose spring constant is 950 N/m. It oscillates with an amplitude of 0.12 m. What is the m
Fudgin [204]

Answer:

velocity = 2.62m/s

Explanation:

950= (4 x A)/0.12

950 x 0.12 = 4 x A

114 = 4 x A

A = 114/4

A = 28.5m/s²

  • U²=2as
  • U² = 2 x 28.5 x 0.12
  • U² = 6.84
  • U = √6.84
  • U = 2.62m/s
3 0
3 years ago
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