In the video, light passing through two slits creates a pattern of bright and dark fringes on a screen. The bright fringes resul
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Answer:
Explanation:
Given:
- mass of skier,
- initial velocity of skier,
- height of the hill,
- spring constant,
<u>final velocity of skier before coming in contact of spring:</u>
Using eq. of motion:
<u>Now the time taken by the skier to reach down:</u>
<u>Now we calculate force using Newton's second law:</u>
<u>∴Compression in spring before the skier momentarily comes to rest:</u>
(a)
Let's analyze the motion along the direction of the incline. We have:
- distance covered: d = 2.00 m
- time taken: t = 1.80 s
- initial velocity: u = 0
- acceleration: a
We can use the following SUVAT equation:
Since u=0 (the block starts from rest), it becomes
So by solving the equation for a, we find the acceleration:
(b) 0.50
There are two forces acting on the block along the direction of the incline:
- The component of the weight parallel to the surface of the incline:
where
m = 3.00 kg is the mass of the block
g = 9.8 m/s^2 is the acceleration due to gravity
is the angle of the incline
This force is directed down along the slope
- The frictional force, given by
where
is the coefficient of kinetic friction
According to Newton's second law, the resultant of the forces is equal to the product between mass and acceleration:
Solving for , we find
(c) 12.3 N
The frictional force acting on the block is given by
where
is the coefficient of kinetic friction
m = 3.00 kg is the mass of the block
g = 9.8 m/s^2 is the acceleration of gravity
is the angle of the incline
Substituting, we find
(d) 6.26 m/s
The motion along the surface of the incline is an accelerated motion, so we can use the following SUVAT equation
where
v is the final speed of the block
u = 0 is the initial speed
a = 1.23 m/s^2 is the acceleration
d = 2.00 m is the distance covered
Solving the equation for v, we find the speed of the block after 2.00 m: