∠A and \angle B∠B are complementary angles. If m\angle A=(2x-10)^{\circ}∠A=(2x−10) ∘ and m\angle B=(x-2)^{\circ}∠B=(x−2) ∘ , the
n find the measure of \angle A∠A.
1 answer:
Answer:
118°
Step-by-step explanation:
Two angles are called complementary when their measures add to 90 degrees.
From the question,
Angle A=(2x-10)°
Angle B=(x-2)°
Both Angles are complementary.
Therefore
Step 1
(2x - 10)° + (x - 2)° = 180°
2x + x - 10 - 2 = 180°
3x - 12 = 180°
3x = 180° + 12
3x = 192°
x = 192/3
x = 64°
Step 2
We are to solve for Angle A
(2x-10)°
Angle A = 2(64 ) - 10
Angle A = 128 - 10
Angle A = 118°
The measure of Angle A = 118°
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