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2 years ago

Help i'm doing missing assignments and this is a lil tricky.

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

3 0

Answer: 25.12 ft

To find the circumference of a circle, multiply the diameter with π (pi)

Formula: 2πr (2 × radius) (π = 3.14)

In the problem...

-----------------------------------------------------------------------------------------------------------------

We can multiply 3.14 by 8 to get the circumference.

3.14 × 8 = 25.12

Hence, 25.12 is the answer, but we can do it another way.

Let me know if you have any questions.

~ Lily, from Brainly.

Note to asker: Hi there, make sure to write down these formulas!

Circumference: 2πr

Area: πr²

Radius: $\frac{diameter}{2}$

Diameter: radius × 2

Have a good day!

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At a bake sale, as student spent $11.00 buying 3 brownies and 5 cookies. His friend spent $3.95 buying 1 brownie and 2 cookies.

riadik2000 [5.3K]

Answer:

$ $$2.25$

Step-by-step explanation:

Let $b =$ the cost of one brownie, $c =$ cost of one cookie

$3b + 5c = 11$

$b+2c = 3.95$

Times $3$ on both sides on the second equation above to get the following:

$3b + 6c = 11.85$

$3b+6c - (3b+5c) = 11.85-11$

$3b+6c-3b-5c = 0.85$

$c = 0.85$

To find the value of $b$ , use substitution:

$b+2c = 3.95$

$b = 3.95-2c$

$= 3.95 - 2\times0.85$

$= 2.25$

$\therefore$ the cost of a brownie is $ $$2.25$

Hope this helps :)

4 0

3 years ago

Solve the inequality y/ -6 is greater than 10

pashok25 [27]

Y<-60
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3 years ago

F⃗ (x,y)=−yi⃗ +xj⃗ f→(x,y)=−yi→+xj→ and cc is the line segment from point p=(5,0)p=(5,0) to q=(0,2)q=(0,2). (a) find a vector pa

DerKrebs [107]

a. Parameterize $C$ by

$\vec r(t)=(1-t)(5\,\vec\imath)+t(2\,\vec\jmath)=(5-5t)\,\vec\imath+2t\,\vec\jmath$

with $0\le t\le1$ .

b/c. The line integral of $\vec F(x,y)=-y\,\vec\imath+x\,\vec\jmath$ over $C$ is

$\displaystyle\int_C\vec F(x,y)\cdot\mathrm d\vec r=\int_0^1\vec F(x(t),y(t))\cdot\frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt$

$=\displaystyle\int_0^1(-2t\,\vec\imath+(5-5t)\,\vec\jmath)\cdot(-5\,\vec\imath+2\,\vec\jmath)\,\mathrm dt$

$=\displaystyle\int_0^1(10t+(10-10t))\,\mathrm dt$

$=\displaystyle10\int_0^1\mathrm dt=\boxed{10}$

d. Notice that we can write the line integral as

$\displaystyle\int_C\vecF\cdot\mathrm d\vec r=\int_C(-y\,\mathrm dx+x\,\mathrm dy)$

By Green's theorem, the line integral is equivalent to

$\displaystyle\iint_D\left(\frac{\partial x}{\partial x}-\frac{\partial(-y)}{\partial y}\right)\,\mathrm dx\,\mathrm dy=2\iint_D\mathrm dx\,\mathrm dy$

where $D$ is the triangle bounded by $C$ , and this integral is simply twice the area of $D$ . $D$ is a right triangle with legs 2 and 5, so its area is 5 and the integral's value is 10.

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Answer:

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Hi I hope you are all okay could someone help me with this math question thankyou !!!

y
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1
√
x
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y
=
7
when
x
=
64
find,
x
when
y
=
8

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