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NikAS [45]
3 years ago
9

PLEASEEEEEEEEEEEEEEE HELP ME WILL GIVE BRAINLIST

Mathematics
1 answer:
miskamm [114]3 years ago
4 0
The answer is 500 i think.
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I don’t understand 7B please help...
joja [24]

Answer:

see explanation

Step-by-step explanation:

let w represent the width then length = w + 7

The perimeter of the rectangle = 2w + 2(w + 7) = 2w + 2w + 14 = 4w + 14

The perimeter is given as 54 m, thus

4w + 14 = 54 ( subtract 14 from both sides )

4w = 40 ( divide both sides by 4 )

w = 10

Thus

width of playground = w = 10 m

length of playground = w + 7 = 10 + 7 = 17 m

7 0
3 years ago
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Susan had 8/10 of a gallon of paint. She used 1/3 of the 8/10 of a gallon to paint her bathroom. How much paint did susan use to
ehidna [41]
First you have to turn 8/10 and 1/3 into equivalent fractions. 8/10 turns into 24/30 and 1/3 turns into 10/30. 24/30 minus 10/30 equals 14/30. After u simplify 14/30 you get 7/15.

Your answer is 7/15
6 0
4 years ago
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ADD 5y to the product of a and b.
frozen [14]

Answer:

5y+a-b

Step-by-step explanation:

3 0
3 years ago
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What is the height of the previous problem?
ioda
Um I actually don’t know the answer I just need coins have a good day maam or sir there is the answer
5 0
3 years ago
How many positive multiples of 7 that are less than 1000 end with the digit 3?
jeyben [28]

Answer:

14

Step-by-step explanation:

Ordinarily, a quick multiplication of 7 by other integers up to 10 indicates that only 7*9 yields 63, i.e ends with 3 as required.

Thus the set of possible multiples of the integer 7 ending with the digit 3 will form the arithmetic series with the first term being Ao = 63 and the common difference being d= 7*10= 70. That is we can see the series in details....

the nth term could be evaluated from the formular

An=Ao+(n-1)d        (1)

The series could be explicitly depicted as follows:

       9*7=63= 63+70*0

(10+9)*7=133 = 63+70*1

(20+9)*7=203=63+70*2

(30+9)*7=273=63+70*3

.................................

(130+9)*7=973=63+70*13

The last 'n' corresponding to the problem statement could be evaluated from equation (1), assuming An=1000:

1000=63+(n-1)*70

1000-63=70(n-1)

937/70=13.38=n-1

n=14.38

Thus the number of possible multiples of 7 less than 1000 ending with digit 3 will be 14.

Check: 7 times 142 is 994, so there are exactly 142 positive multiples of 7 less than 1000.

One tenth of these, ignoring the decimal fraction, end with a digit of 3.

5 0
4 years ago
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