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3 years ago

Helpppppppppppppppppppppppppppp

Mathematics

1 answer:

luda_lava [24]3 years ago

8 0

Hi the answer should be 4

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Math, yes I don't know if I got it right

olga nikolaevna [1]

Answer:

4*(n)^2

Step-by-step explanation:

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2 years ago

Read 2 more answers

Cat face x+4/5=45 sa il aflu pe x

love history [14]

Given:

The equation is

$x+\dfrac{4}{5}=45$

To find:

The value of x.

Solution:

We have,

$x+\dfrac{4}{5}=45$

Isolating the variable, we get

$x=45-\dfrac{4}{5}$

$x=\dfrac{225-4}{5}$

$x=\dfrac{221}{5}$

$x=44.2$

Therefore, the value of x is 44.2.

6 0

3 years ago

I need help with number 2 please.

Vedmedyk [2.9K]

The answer is 73.33333333 (repeated). You can also write it as 73 or 73.3 with a line over the 3 (after the decimal point) to indicate it being repeated.

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3 years ago

kyle took at total of 8 quizzes in the first 4 weeks of school. How many weeks of school will he have to attend before he will h

Elden [556K]

Answer:

6 weeks

Step-by-step explanation:

8 quizzes = 4 weeks

So 2 quizzes/week

It will take her 12/2 weeks (6) to finish 12 quizzes

-Chetan K

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2 years ago

Integration of ∫(cos3x+3sinx)dx

Murljashka [212]

Answer:

$\boxed{\pink{\tt I = \dfrac{1}{3}sin(3x) - 3cos(x) + C}}$

Step-by-step explanation:

We need to integrate the given expression. Let I be the answer .

$\implies\displaystyle\sf I = \int (cos(3x) + 3sin(x) )dx \\\\\implies\displaystyle I = \int cos(3x) + \int sin(x)\ dx$

Let u = 3x , then du = 3dx . Henceforth 1/3 du = dx .
Now , Rewrite using du and u .

$\implies\displaystyle\sf I = \int cos\ u \dfrac{1}{3}du + \int 3sin \ x \ dx \\\\\implies\displaystyle \sf I = \int \dfrac{cos\ u}{3} du + \int 3sin\ x \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}\int \dfrac{cos(u)}{3} + \int 3sin(x) dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3} sin(u) + C +\int 3sin(x) dx \\\\\implies\displaystyle \sf I = \dfrac{1}{3}sin(u) + C + 3\int sin(x) \ dx \\\\\implies\displaystyle\sf I = \dfrac{1}{3}sin(u) + C + 3(-cos(x)+C) \\\\\implies \underset{\blue{\sf Required\ Answer }}{\underbrace{\boxed{\boxed{\displaystyle\red{\sf I = \dfrac{1}{3}sin(3x) - 3cos(x) + C }}}}}$

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3 years ago