Answer:
A
Step-by-step explanation:
9 = (1/27)^(a+3)
3² = (3^-3)^(a+3)
3² = 3^(-3a-9)
2 = -3a-9
-3a = 11
a = -11/3
Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
6x-25 six and a number(x) decreased by 25
Answer:
[- 4, ∞ )
Step-by-step explanation:
the expression inside the radical must be greater than or equal to zero
x +4 ≥ 0 ⇔ x ≥ - 4
domain: x ∈ [- 4, ∞ )
Answer:
f(g(x)) = 5(3x + 5) = 15x + 25
g(f(x)) = 3(5x) + 5 = 15x + 5
Step-by-step explanation:
Since you didn't say what you were trying to find, I'll give you a couple things you may have been trying to find.
f(g(x)) = 5(3x + 5) = 15x + 25
g(f(x)) = 3(5x) + 5 = 15x + 5
