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3 years ago

Water is being lost from earth at the rate per a year of what percentage

Chemistry

2 answers:

natta225 [31]3 years ago

8 0

At least 14 to 18 percent of water is being lost each year. I really hope this helps :D

Tomtit [17]3 years ago

6 0

Answer:

The current loss figure is equivalent to ~25,920 liters per day or 9,467 m3 per year

It isn't a percentage, but I hope that helps a little

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What is 0.13592 in scientific notation

mel-nik [20]

to write 0,0045 in scientific notation, we will have to move the decimal point three point to right, which literally means multiplying by 1000=103 . Hence in scientific notation 0.0045=4.5×10−3 (note that as we have moved decimal three point to right we are multiplying by 10−3 this is an example

6 0

3 years ago

Read 2 more answers

Consider the following intermediate chemical equations.

olga nikolaevna [1]

I think that would be the third one

5 0

3 years ago

Read 2 more answers

A 60.0 mL solution of 0.112 M sulfurous acid (H2SO3) is titrated with 0.112 M NaOH. The pKa values of sulfurous acid are 1.857 (

djverab [1.8K]

Answer:

a)4.51

b) 9.96

Explanation:

Given:

NaOH = 0.112M

H2S03 = 0.112 M

V = 60 ml

H2S03 pKa1= 1.857

pKa2 = 7.172

a) to calculate pH at first equivalence point, we calculate the pH between pKa1 and pKa2 as it is in between.

Therefore, the half points will also be the middle point.

Solving, we have:

pH = (½)* pKa1 + pKa2

pH = (½) * (1.857 + 7.172)

= 4.51

Thus, pH at first equivalence point is 4.51

b) pH at second equivalence point:

We already know there is a presence of SO3-2, and it ionizes to form

SO3-2 + H2O <>HSO3- + OH-

$Kb = \frac{[ HSO3-][0H-]}{SO3-2}$

$Kb = \frac{10^-^1^4}{10^-^7^.^1^7^2} = 1.49*10^-^7$

[HSO3-] = x = [OH-]

mmol of SO3-2 = MV

= 0.112 * 60 = 6.72

We need to find the V of NaOh,

V of NaOh = (2 * mmol)/M

= (2 * 6.72)/0.122

= 120ml

For total V in equivalence point, we have:

60ml + 120ml = 180ml

[S03-2] = 6.72/120

= 0.056 M

Substituting for values gotten in the equation $Kb=\frac{[HSO3-][OH-]}{[SO3-2]}$

We noe have:

$1.485*10^-^7=\frac{x*x}{(0.056-x)}$

$x = [OH-] = 9.11*10^-^5$

$pOH = -log(OH) = -log(9.11*10^-^5)$

=4.04

pH = 14- pOH

= 14 - 4.04

= 9.96

The pH at second equivalence point is 9.96

4 0

3 years ago

A ______ in medicine is a form of scientific argumentation in which evidence is used to rule out claims and support the best con

Gekata [30.6K]

Answer: Scientific reasoning

Explanation:

A scientific reasoning can be defined as the justification which connects the evidence with that of the claim and it rules out all those claims that are not supported by any evidence. It explains the fact that how evidence can support a claim and scientifically acceptable conclusion can be drawn. An argument is always based on one or more claims which can either be true or evidentially proved.

5 0

3 years ago

Solve by a 1 variable equation -3(x-3)=x+9-4x

Otrada [13]

-3(x - 3) = x + 9 - 4x

Firstly, before we simplify the whole thing altogether, let's simplify each respective side. Distribute accordingly on the left side (the number outside the parentheses is distributed to the numbers inside the parentheses), and we can add the numbers with variables together on the right side.

-3x + 9 = -3x + 9

Now, let's add 3x to both sides, to simplify both sides now. This leaves us with: 1, I believe, since -3 ÷ -3 is 1.

x = x, and since x also equals to 1, our answer is 1. And once you check, substituting 1 for x, you will find that 1 is the correct answer.

5 0

3 years ago