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vazorg [7]
3 years ago
7

When 50.0 mL of 0.100M iron (III) chloride is mixed with 50.0 mL of 0.100M lead (II) nitrate, why should we determine which reac

tant
is limiting?
Chemistry
1 answer:
White raven [17]3 years ago
4 0
50.000.50.0050.00 I chloride mixed with 500 ml
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A) 3 and 4<br><br> b) 2 and 3<br><br> c) 1 and 2<br><br> d) 1 and 4
tatiyna
<h3>Answer:</h3>

d) 1 and 4

<h3>Explanation:</h3>
  • Elements are made up of particles known as atoms.
  • Atoms of the same element have the same properties as the element.
  • The atoms of an element may differ in terms of the number of neutrons and have a different mass number, such atoms are known as isotopes.
  • However, the isotopes have an equal number of protons or atomic number.
  • In this case, atom 1 has a mass number of 20 and an atomic number of 10 while atom 4 has a mass number of 21 and an atomic number of 21.
  • Therefore, atom 1 and 4 are isotopes of element E.

4 0
3 years ago
Help<br> Please! Thank you! Work would be really awesome! Have a good day ❤️
ipn [44]

Answer: 3 O2

Explanation: This is a combustion reaction. A hydrocarbon reacts with oxygen gas to produce CO2 and H2O.

C2H5OH + 3 O2 => 2 CO2 + 3 H2O

6 0
3 years ago
What is anus?plss help​
Veronika [31]
Please help me!!!!!!

6 0
3 years ago
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at normal body temperature, 37 degree C, Kw = 2.4x10^-14. Calculate [H+] and [OH-] for a neutral solution at this temperature.
hichkok12 [17]

Answer:

1.55x10⁻⁷ = [H⁺] = [OH⁻]

Explanation:

The water equilibrium at a certain temperature is represented as follows:

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Where Kw is represented as:

Kw = [H⁺] [OH⁻]

In a neutral solution, [H⁺] = [OH⁻], thus, at 37°C:

2.4x10⁻¹⁴ = [H⁺]²

<em>1.55x10⁻⁷ = [H⁺]</em>

As The water equilibrium at a certain temperature is represented as follows:

H₂O(l) ⇄ H⁺(aq) + OH⁻(aq)

Where Kw is represented as:

Kw = [H⁺] [OH⁻]

In a neutral solution, [H⁺] = [OH⁻], thus, at 37°C:

2.4x10⁻¹⁴ = [H⁺]²

<em>1.55x10⁻⁷M = [H⁺]</em>

As [H⁺] = [OH⁻], <em>[OH⁻] = 1.55x10⁻⁷M</em>

5 0
3 years ago
The nucleus of an atom of Cobalt-58 contains:
Rashid [163]
Sorry but don't get it (no offense; will figure out later)
3 0
3 years ago
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