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zhannawk [14.2K]
3 years ago
6

Calculate the current,if charges is 100c pass through ​

Physics
1 answer:
xenn [34]3 years ago
3 0

Answer:

An amp is one C per second. Two minutes is 120 seconds. So current is 10 C/120 sec which is 1/12 th of an Amp.

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Increase, same, same

Explanation:

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Consider the expression below. Assume m is an integer. 6m(2m + 18) Enter an expression in the box that uses the variable m and m
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6x2=12m
6x18=108
12m+108
Simplified: m+9 bc 12/12 and 108/12
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How are an element's abundance in nature and percent composition related?
Tatiana [17]
Because they both have to do with chemistry
4 0
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A practical rule is that a radioactive nuclide is essentially gone after 10 half-lives. What percentage of the original radioact
ArbitrLikvidat [17]

Answer:

  • 0.09 % of the original radioactive nucllde its left after 10 half-lives
  • It will take 241,100 years for 10 half-lives of plutonium-239 to pass.

Explanation:

The equation for radioactive decay its:

N ( t) \ = \ N_0 \ e^{ \ -  \frac{t}{\tau}},

where N(t) its quantity of material at time t, N_0 its the initial quantity of material and \tau its the mean lifetime of the radioactive element.

The half-life t_{\frac{1}{2}} its the time at which the quantity of material its the half of the initial value, so, we can find:

N (t_{\frac{1}{2} }) \ = \ N_0 \ e^{ \ -  \frac{t_{\frac{1}{2}}}{\tau}} \ = \frac{N_0}{2}

so:

\ N_0 \ e^{ \ -  \frac{t_{\frac{1}{2}}}{\tau}} \ = \frac{N_0}{2}

e^{ \ -  \frac{t_{\frac{1}{2}}}{\tau}} \ = \frac{1}{2}

-  \frac{t_{\frac{1}{2}}}{\tau}} \ = - \ ln( 2 )

t_{\frac{1}{2}}\ = \tau ln( 2 )

So, after 10 half-lives, we got:

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ e^{ \ -  \frac{10 \  t_{\frac{1}{2}}}{\tau}}

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ e^{ \ -  \frac{10 \  \tau \ ln( 2 ) }{\tau}}

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ e^{ \ -  10 \  \ ln( 2 ) }

N ( 10 \  t_{\frac{1}{2}}) \ = \ N_0 \ * \ 9.76 * 10^{-4}

So, we got that a 0.09 % of the original radioactive nucllde its left.

Putonioum-239 has a half-life of 24,110 years. So, 10 half-life will take to pass

10 \ * \ 24,110 \ years \ = \ 241,100 \ years

It will take 241,100 years for 10 half-lives of plutonium-239 to pass.

7 0
3 years ago
Read 2 more answers
A ball is thrown horizontally from the top of a building 0.10 km high. The ball strikes the ground at a point 65 m horizontally
stepladder [879]

Answer:  well the time it takes to fall 100m is the same time it takes to travel 65m horizontally.  

The time to fall vertically, t is sqrt(2d/g). [this comes from d = 1/2at^2]  

so t = sqrt(2*100/9.8) = 4.52s.  

The vertical speed at that time is g*t = 9.8*4.52 = 44.3m/s  

The horizontal speed is the horizontal distance over the same 4.52s, = 65/4.52 = 14.4m/s.  

so the final velocity is = sqrt(44.3^2 + 14.4^2) = 46.6m/s

Explanation: yes

6 0
3 years ago
Read 2 more answers
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