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zhannawk [14.2K]
3 years ago
6

Calculate the current,if charges is 100c pass through ​

Physics
1 answer:
xenn [34]3 years ago
3 0

Answer:

An amp is one C per second. Two minutes is 120 seconds. So current is 10 C/120 sec which is 1/12 th of an Amp.

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FIRST TO ANSWER CORRECTLY GETS BRAIBLIEST!!
WINSTONCH [101]
Brushes, battery terminals, commutator, armature, magnets
7 0
2 years ago
An automobile with 0.500 m radius tires travels 80,000 km before wearing them out. How many revolutions do the tires make, negle
Zinaida [17]

Answer:

n = 25,464,790.89 revolutions

The tires have made 25,464,790.89 revolutions

Explanation:

Given;

Radius of tires r = 0.5 m

Total distance travelled d = 80,000 km = 80,000,000 m

1 revolution = 2πr

Total distance d = number of revolutions n × 2πr

d = n×2πr

d = 2πnr

Making n the subject of formula;

n = d/2πr

Substituting the given values;

n = (80,000,000)/(2×π×0.5)

n = 25,464,790.89470 revolutions

n = 25,464,790.89 revolutions

The tires have made 25,464,790.89 revolutions

5 0
3 years ago
What is the mass of an object that requires a force of 30 N to accelerate at a rate of 5 m/sec2 ?
Anastaziya [24]
M=F/A
Which means 30 divided by 5 m/s is 6kg(mass)
8 0
2 years ago
As the kinetic energy of an object increases, so does the _________ energy produced. A) heat B) light C) atomic D) potential
IrinaK [193]

Answer:

A) heat

Explanation:

As kinetic energy increases, so does the heat energy produced. The faster the molecules move, the more heat that is generated.

5 0
3 years ago
Read 2 more answers
The initial and final velocities of two blocks experiencing constant acceleration are respectively −7.45 m/s and 14.9 m/s. (a) T
ikadub [295]

Answer:

a) a_{1}=3.7 m/s^{2}

b) a_{2}=3.68 m/s^{2}

Explanation:

a) The displacement of the first object is 22.5 m, so we can use the next equation:

v_{f}^{2}=v_{i}^{2}+2a\Delta x

a=\frac{v_{f}^{2}-v_{i}^{2}}{2x}

a=\frac{14.9^{2}-(-7.45)^{2}}{2*22.5}

a_{1}=3.7 m/s^{2}

positive acceleration.

b) Using the same equation we can find the second value of the acceleration:

a=\frac{v_{f}^{2}-v_{i}^{2}}{2x}

a=\frac{14.9^{2}-(-7.45)^{2}}{2*22.6}

a_{2}=3.68 m/s^{2}

positive acceleration.

I hope it helps you!

8 0
3 years ago
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