It depends, You have to have the length and the width of the crest wave.
"...volume remains constant/same"
hope it helps you
Answer:
Acceleration
Explanation:
The quantity of the rate of change of velocity is termed the acceleration of the body.
Acceleration is the rate of change of velocity with time;
A =
A is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
The ball moves by uniformly accelerated motion, and its vertical position at time t is described by the following law
![y(t) = h+v_0t - \frac{1}{2}gt^2](https://tex.z-dn.net/?f=y%28t%29%20%3D%20h%2Bv_0t%20-%20%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2%20)
where
![h=4.21 m](https://tex.z-dn.net/?f=h%3D4.21%20m)
is the initial height from which the ball starts its motion
![v_0=1.53 m/s](https://tex.z-dn.net/?f=v_0%3D1.53%20m%2Fs)
is the initial velocity of the ball
![g=9.81 m/s^2](https://tex.z-dn.net/?f=g%3D9.81%20m%2Fs%5E2)
is the gravitational acceleration
The time in which the ball reaches the ground is the time t at which the vertical position y(t) becomes zero:
![0= h + v_0 t - \frac{1}{2}gt^2](https://tex.z-dn.net/?f=0%3D%20h%20%2B%20v_0%20t%20-%20%5Cfrac%7B1%7D%7B2%7Dgt%5E2)
Which means
![0=4.21 + 1.53 t - 4.9 t^2](https://tex.z-dn.net/?f=0%3D4.21%20%2B%201.53%20t%20-%20%204.9%20t%5E2%20)
whose solutions are:
![t=-0.78 s](https://tex.z-dn.net/?f=t%3D-0.78%20s)
![t=1.10 s](https://tex.z-dn.net/?f=t%3D1.10%20s)
Neglecting the negative solution (since it has no physical meaning), we can say that the ball reaches the ground after 1.10 s.