Answer :  The value of second ionization energy of Ca is 1010 kJ.
Explanation :  
The formation of calcium oxide is,

 = enthalpy of formation of calcium oxide = -635 kJ
 = enthalpy of formation of calcium oxide = -635 kJ
The steps involved in the born-Haber cycle for the formation of  :
:
(1) Conversion of solid calcium into gaseous calcium atoms.

 = sublimation energy of calcium = 193 kJ
 = sublimation energy of calcium = 193 kJ
(2) Conversion of gaseous calcium atoms into gaseous calcium ions.

 = first ionization energy of calcium = 590 kJ
 = first ionization energy of calcium = 590 kJ
(3) Conversion of gaseous calcium ion into gaseous calcium ions.

 = second ionization energy of calcium = ?
 = second ionization energy of calcium = ?
(4) Conversion of molecular gaseous oxygen into gaseous oxygen atoms.


 = dissociation energy of oxygen =
 = dissociation energy of oxygen = 
(5) Conversion of gaseous oxygen atoms into gaseous oxygen ions.

 = first electron affinity energy of oxygen = -141 kJ
 = first electron affinity energy of oxygen = -141 kJ
(6) Conversion of gaseous oxygen ion into gaseous oxygen ions.

 = second electron affinity energy of oxygen = 878 kJ
 = second electron affinity energy of oxygen = 878 kJ
(7) Conversion of gaseous cations and gaseous anion into solid calcium oxide.

 = lattice energy of calcium oxide = -3414 kJ
 = lattice energy of calcium oxide = -3414 kJ
To calculate the overall energy from the born-Haber cycle, the equation used will be:

Now put all the given values in this equation, we get:


Therefore, the value of second ionization energy of Ca is 1010 kJ.