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seropon [69]
3 years ago
5

After scientists get the results of their experiments, they...

Chemistry
1 answer:
ioda3 years ago
4 0

Answer:

Form a conclusion

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How many Ne atoms are contained in 32.0 g of the element?
Svetlanka [38]
Mass atomic of Ne=20.18 u
Therefore:
molar mass=20.18 g/1 mol

1 mole=6.022*10²³ particles (atoms or molecules)

Then: 6.022*10²³ atoms are contained in 20.18g

Now, We can solve this problem by the three rule.

6.022*10²³ atoms-------------------20.18 g
x------------------------------------------32 g

x=(6.022*10²³ atoms * 32 g)/20.18 g=9.55*10²³ atoms.

Answer: 9.55*10²³ Ne atoms are contained in 32 g of the element.
3 0
3 years ago
All energy originates from the _______.
Phantasy [73]

Answer:

sun

Explanation:

because all plants use energy from the sun to make food and grow

7 0
3 years ago
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Explain The relationship between engineering science and technology
erik [133]


The Difference Between Science, Engineering, and Technology. Science is the study of the natural world as it is; engineering is creating new tools, devices, and processes based on scientific knowledge; technology is the sum total of all the engineered tools, devices and processes available.
5 0
3 years ago
Determine whether the given compound name or formula contains a polyatomic ion. N H 4 C l Choose... Magnesium sulfate Choose...
Morgarella [4.7K]

Answer:

NH₄Cl, Magnesium sulfate, KCN

Explanation:

Determine whether the given compound name or formula contains a polyatomic ion.

  • NH₄Cl. YES. It contains the polyatomic ion ammonium NH₄⁺.
  • Magnesium sulfate. YES.  It contains the polyatomic ion sulfate SO₄²⁻.
  • Sodium phosphide Na₃P. NO.
  • SO₃. NO.
  • Calcium hydroxide Ca(OH)₂. NO.
  • KCN. YES. It contains the polyatomic ion cyanide CN⁻.
4 0
3 years ago
The half life of radon-222 is 3.8 days. How Much of a 100g sample is left after 15.2 days
professor190 [17]

Answer:  

6.2 g  

Explanation:  

In a first-order decay, the formula for the amount remaining after <em>n</em> half-lives is  

N = \frac{N_{0}}{2^{n}}  

where  

<em>N</em>₀ and <em>N</em> are the initial and final amounts of the substance  

1. Calculate the <em>number of half-lives</em>.  

If t_{\frac{1}{2}} = \text{3.8 da}  

n = \frac{t}{t_{\frac{1}{2}}} = \frac{\text{15.2 da}}{\text{3.8 da}}= \text{4.0}

2. Calculate the <em>final mass</em> of the substance.  

\text{N} = \frac{\text{100 g}}{2^{4.0}} = \frac{\text{100 g}}{16} = \text{6.2 g}

4 0
3 years ago
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