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3 years ago

11

Help me please thanks in advance

1 answer:

Xelga [282]3 years ago

4 0

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From up to down ;

_________________________________

The first box :

$f(n) = 3. ({2})^{n - 1}$

The second box :

$f(n) = 2. ({4})^{n - 1}$

The third box :

$f(n) = 2. ({6})^{n - 1}$

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Answer:

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Step-by-step explanation:

<em>4)</em> $9d - 5 = 4$

Adding 5 on both the sides ,

$= > 9d - 5 + 5 = 4 + 5$

$= > 9d = 9$

Dividing both the sides by 9 ,

$= > \frac{9d}{9} = \frac{9}{9}$

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<em>5)</em> $6 - 3w = - 27$

Substracting 6 from both the sides ,

$6 - 3w - 6 = - 27 - 6$

$= > - 3w = - 33$

Dividing both the sides by -3 ,

$= > \frac{ - 3w}{ - 3} = \frac{ - 33}{ - 3}$

$= > w = 11$

<em>6)</em> $- 4 = \frac{q}{8} - 19$

Adding 19 on both the sides ,

$\frac{q}{8} - 19 + 19 = - 4 + 19$

$= > \frac{q}{8} = 15$

Multiplying both the sides by 8 ,

$= > \frac{q}{8} \times 8 = 15 \times 8$

$= > q = 120$

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