1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
zhenek [66]
3 years ago
13

A chemist adds of a potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate t

he chemist has added to the flask
Chemistry
1 answer:
Viefleur [7K]3 years ago
7 0

Answer:

3.41 g

Explanation:

<em>A chemist adds 260.0 mL of a 0.0832 M potassium permanganate solution to a reaction flask. Calculate the mass in grams of potassium permanganate the chemist has added to the flask.</em>

Step 1: Given data

  • Volume of the solution (V): 260.0 mL (0.2600 L)
  • Molar concentration of the solution (C): 0.0832 M (0.0832 mol/L)

Step 2: Calculate the moles (n) of potassium permanganate added

We will use the following expression.

n = C × V

n = 0.0832 mol/L × 0.2600 L = 0.0216 mol

Step 3: Calculate the mass corresponding to 0.0216 moles of potassium permanganate

The molar mass of potassium permanganate is 158.03 g/mol.

0.0216 mol × 158.03 g/mol = 3.41 g

You might be interested in
What SI Unit would best be used to express the height of your classroom ceiling?
ivolga24 [154]

SI unit of length - meters
3 0
3 years ago
What are the formulas?
shtirl [24]
Formulas are like steps to solve an equation but in cemistry a formula is 2 or more elements combined to make something

7 0
4 years ago
Read 2 more answers
Severe droughts cause some lands to become deserts, and this process leads to
Alona [7]
All above


Severe Droughts can make land unlivable, as all living things need food and water to survive
7 0
3 years ago
Read 2 more answers
State the definition of the partial molar Gibbs energy.
balu736 [363]

Explanation :

As we know that the Gibbs free energy is not only function of temperature and pressure but also amount of each substance in the system.

G=G(T,P,n_1,n_2)

where,

n_1\text{ and }n_2 is the amount of component 1 and 2 in the system.

Partial molar Gibbs free energy : The partial derivative of Gibbs free energy with respect to amount of component (i) of a mixture when other variable (T,P,n_j) are kept constant are known as partial molar Gibbs free energy of i^{th} component.

For a substance in a mixture, the chemical potential (\mu) is defined as the partial molar Gibbs free energy.

The expression will be:

\bar{G_i}=\mu_i=\frac{\partial G}{\partial n_i}_{(T,P,n_j)}

where,

T = temperature

P = pressure

n_i\text{ and }n_j is the amount of component 'i' and 'j' in the system.

4 0
3 years ago
How much excess reactant is left over when 17.0 g of potassium hydroxide (KOH) reacts with
dolphi86 [110]

Answer:

4.56 g of KOH

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KOH + Fe(NO₃)₂ —> Fe(OH)₂ + 2KNO₃

Next, we shall determine the masses of KOH and Fe(NO₃)₂ that reacted from the balanced equation. This is can be obtained as:

Molar mass of KOH = 39 + 16 + 1 = 56 g/mol

Mass of KOH from the balanced equation = 2 × 56 = 112 g

Molar mass of Fe(NO₃)₂ = 56 + 2[14 + (16×3)]

= 56 + 2[14 + 48)]

= 56 + 2[62]

= 56 + 124

= 180 g/mol

Mass of Fe(NO₃)₂ from the balanced equation = 1 × 180 = 180 g

SUMMARY:

From the balanced equation above,

112 g of KOH reacted with 180 g of Fe(NO₃)₂

Next, we shall determine the limiting reactant and the excess reactant. This can be obtained as follow:

From the balanced equation above,

112 g of KOH reacted with 180 g of Fe(NO₃)₂.

Therefore, 17 g of KOH will react with = (17 × 180)/112 = 27.32 g of Fe(NO₃)₂

From the calculations made above, we can see that it will take a higher mass (i.e 27.32 g) of Fe(NO₃)₂ than what was given (i.e 20 g) to react completely with 17 g of KOH.

Therefore, Fe(NO₃)₂ is the limiting reactant and KOH is the excess reactant.

Next, we shall determine the mass of the excess reactant that reacted. This can be obtained as follow:

From the balanced equation above,

112 g of KOH reacted with 180 g of Fe(NO₃)₂.

Therefore Xg of KOH will react with 20 g of Fe(NO₃)₂ i.e

Xg of KOH = (112 × 20)/180

Xg of KOH = 12.44 g

Thus, 12.44 g of KOH reacted.

Finally, we shall determine the leftover mass of the excess reactant.

The excess reactant is KOH. The leftover mass can be obtained as follow:

Mass of KOH given = 17 g

Mass of KOH that reacted = 12.44 g

Mass of KOH leftover =?

Mass of KOH leftover = (Mass of KOH given) – (Mass of KOH that reacted)

Mass of KOH leftover = 17 – 12.44

Mass of KOH leftover = 4.56 g

Thus, the excess reactant (i.e KOH) that is left over is 4.56 g

3 0
3 years ago
Other questions:
  • Do you think it was fair to name the experiment after Rutherford while ignoring the other two scientists?
    7·1 answer
  • Metaphor for the word solid
    11·1 answer
  • Plz answer 3 ,4,5 thanks
    13·1 answer
  • NO2+H4➡2 H2O+N What are the elements
    10·2 answers
  • If you just want points just say so this can lead me to failing 10th if I don’t pass this quiz so if you don’t know just say so
    12·1 answer
  • Someone pls help I’m in such a hurry!!
    6·1 answer
  • If you hear on the news that the epicenter of an earthquake is at "Union City," this means:
    11·2 answers
  • Is detergent unicellular
    9·1 answer
  • I NEED HELP ASAP DUE TOMORROW!!!! I WILL GIVE BRAINLIEST!!!
    13·2 answers
  • WILL MARK BRAINLY<br> i dont think its gas
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!