Answer:
CO2
Explanation:
(I Just took the test)
At STP 1 mol=22.4 Liters, so we now know that it is asking for which of the gasses has a molar mass of 44, and CO2 is th only one with that molar mass
First, is to solve the molar mass of the herbicide, with a formula
<span>C3H8NO5P
C3 = 12 ( 3 ) = 36
H8 = 1 ( 8 ) = 8
N = 14
O5 = 16 ( 5 ) = 80
P = 31
so in total the molar mass of </span><span>C3H8NO5P is 36 + 8 + 14 + 80 + 31 = 169 g/mol
number of moles = 783.5 g ( 1 mol / 169 g)
number of moles = 4.64 mol </span><span>C3H8NO5P</span>
Answer:
Explanation:
Hello there!
In this case, since the equation for the calculation of dilutions is:
Whereas M is the molarity and V the volume, because the final concentration is lower than the initial. Thus, since we are asked to calculate the final volume, we solve for V2 as follows:
Best regards!
the larger the molecules of the solute are, the larger is their molecular weight and their size.
