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harkovskaia [24]
3 years ago
15

Anyone know the parts of this cell? Please and thank you!

Chemistry
1 answer:
aniked [119]3 years ago
4 0

Answer: A, Nucleus

B, Cell memebrane

C, vacuole

D, Chloroplast, mitocondria, amyloplast.

Explanation:

These only work if this is a plant cell which you did not specify.

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The mass number of 3 isotopes of magnesium are 24,25,26.what is the mass number of the most abundant isotope of magnesium.​
Anarel [89]

Answer:

24.4 amu or g/mole

Explanation:

24 x 0.790 = 19.0 amu

25 x 0.100 = 2.50 amu

26 x 0.110 = 2.86 amu

(Because of the 19.0, the sig figs go only to the 1/10 decimal place)

19.0 + 2.5 + 2.9 = 24.4 amu or g/mole

7 0
2 years ago
In a chemical reaction, 36 grams of hydrochloric acid reacts with 40 grams of sodium hydroxide to produce sodium chloride and wa
Elena L [17]
The answer is <span>The mass of sodium chloride formed is less than 76 grams.
</span>
Remember Mass is never gained or loss in any chemical reactions

So,

hydrochloric acid  + sodium hydroxide  =>  <span>sodium chloride + water
                          Total 76 gram                         Total will also 76 gram

In this case, the mass of sodium chloride will be less than 76 gram because we need to take out the mass of the water.

</span>
3 0
3 years ago
Read 2 more answers
If 1.00 g of a hydrocarbon is combusted and found to produce 3.14 g of co2, what is the empirical formula of the hydrocarbon?
photoshop1234 [79]
The combustion reaction is as expressed,

                CxHy + O2 --> CO2 + H2O

The mass fraction of carbon in CO2 is 3/11. Hence,
       mass of C in CO2 = (3.14 g)(3/11) = 0.86 g C.

Given that we have 1 g of the hydrocarbon, the mass of H is equal to 0.14 g. 

     moles of C = 0.86 g C / 12 g = 0.0713
     moles of H = 0.14 g H / 1 g  = 0.14

The empirical formula for the hydrocarbon is therefore, CH₂.
7 0
2 years ago
Match each organ to its function. Tiles bone heart stomach lung Pairs pumps blood through the body Both provides structure for t
solniwko [45]
Heart: Pumps blood through the body
Bone: Provides structure
Stomach: Breaks down food into small particles
Lungs: Oxygenates blood
7 0
3 years ago
Read 2 more answers
Be sure to answer all parts. Consider the formation of ammonia in two experiments. (a) To a 1.00−L container at 727°C, 1.30 mol
Sonbull [250]

<u>Answer:</u> The value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

<u>Explanation:</u>

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

                N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)

<u>Initial:</u>            1.30       1.65

<u>At eqllm:</u>       1.30-x    1.65-3x             2x

Evaluating the value of 'x'

\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol

The expression of K_c for above equation follows:

K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}

Equilibrium moles of nitrogen gas = (1.30-x)=(1.30-0.05)=1.25mol

Equilibrium moles of hydrogen gas = (1.65-x)=(1.65-0.05)=1.60mol

Putting values in above expression, we get:

K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}

Calculating the K_c' for the given chemical equation:

2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)

K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2

Hence, the value of K_c for 2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g) reaction is 5.13\times 10^2

8 0
3 years ago
Read 2 more answers
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