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2 years ago

Please help this is on my exam

Chemistry

1 answer:

Vikentia [17]2 years ago

6 0

Answer:

D. The time of day

Explanation:

The independent variable is the variable the experimenter changes or controls and is assumed to have a direct effect on the dependent variable

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Please help ill mark branliest (im using the last of my points for this so please don't scam me)

vichka [17]

Answer:

ok :)

Explanation: genetically modified organisms (GMOs) are being made by inserting a gene from an external source such as viruses, bacteria, animals or plants (etc) into foods. Genetically modified foods seem to be not as healthy as unmodified foods, according to research. also many people are against it due to the fact that some people go overboard and add too many genetically modified organisms, which causes health risks and unfortunately harms people. sometimes genetically modified food contains toxins and antibiotics. srry i couldnt find much on the process but this is based off my background knowledge so yeah

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2 years ago

Which pair of compounds represents one Arrhenius acid and one Arrhenius base?

erica [24]

Answer: C. HNO3 and NaOH

Explanation:

Arrhenius acid produces hydogen ion (H+) when dissolved in water. An example of Arrhenius acid is HNO3.

Arrhenius base produces hydroxyl ion (OH-) when dissolved water. An example of Arrhenius base is NaOH.

4 0

2 years ago

A. Which reactant is the limiting reagent?

Tasya [4]

Answer:

a. Zinc is the limiting reactant.

b. $m_{ZnBr_2}^{by\ Zn}=162.61gZnBr_2$

c. $m_{Br_2}^{leftover}=6.6g$

Explanation:

Hello there!

a. In this case, when zinc metal reacts with bromine, the following chemical reaction takes place:

$Zn+Br_2\rightarrow ZnBr_2$

Thus, since zinc and bromine react in a 1:1 mole ratio, we can compute their reacting moles to identify the limiting reactant:

$n_{Zn}=47.2g*\frac{1mol}{65.38g} =0.722molZn\\\\n_{Br_2}=122g*\frac{1mol}{159.8g} =0.763molBr_2$

Thus, since zinc has the fewest moles we infer it is the limiting reactant.

b. Here, we compute the grams of zinc bromide via both reactants:

$m_{ZnBr_2}^{by\ Zn}=0.722molZn*\frac{1molZnBr_3}{1molZn} *\frac{225.22gZnBr_2}{1molZnBr_2} =162.61gZnBr_2\\\\m_{ZnBr_2}^{by\ Br_2}=0.763molBr_2*\frac{1molZnBr_3}{1molBr_2} *\frac{225.22gZnBr_2}{1molZnBr_2} =171.95gZnBr_2$

That is why zinc is the limiting reactant, as it yields the fewest moles of zinc bromide product.

c. Here, since just 0.722 mol of bromine would react, we compute the corresponding mass:

$m_{Br_2}^{reacted}=0.722molBr_2*\frac{159.8gBr_2}{1molBr_2} =115.4gBr_2$

Thus, the leftover of bromine is:

$m_{Br_2}^{leftover}=122g-115.4g\\\\m_{Br_2}^{leftover}=6.6g$

Best regards!

8 0

2 years ago

What is the percent composition of Sb2F3.What is the percent composition of F in this molecule? Round the answer to five signifi

poizon [28]

Answer:

$\%F=18.967\%$

Explanation:

Hello,

In this case, a percent composition is computed by considering the atomic mass of each element in the compound as well as the number of atoms and the molar mass of the compound. Thus, Sb2F3 has a molar mass of 300.52 g/mol, antimony has an atomic mass of 121.76 g/mol and fluorine 19.0 g/mol, therefore, the percent composition of fluorine which has three atoms with five significant figures is:

$\% F=\frac{3*19.0g/mol}{300.52g/mol}*100\%\\ \\\%F=18.967\%$

Best regards.

3 0

2 years ago

What is N3I8 chemical compound name?

joja [24]

Answer:

When naming molecular compounds prefixes are used to dictate the number of a given element present in the compound. ” mono-” indicates one, “di-” indicates two, “tri-” is three, “tetra-” is four, “penta-” is five, and “hexa-” is six, “hepta-” is seven, “octo-” is eight, “nona-” is nine, and “deca” is ten.

Explanation:

8 0

2 years ago