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3 years ago

12

What is the lightest material ever created by the hands of men

1 answer:

lutik1710 [3]3 years ago

6 0

The world's lightest material is carbon aerogel which has a mass of only 0.16 milligram and it is even lighter than aerographite.

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Calculate the Molecular or Formula massof each of the following:

DiKsa [7]

Explanation:

Molar mass

The mass present in one mole of a specific species .

The molar mass of a compound , can easily be calculated as the sum of the all the individual atom multiplied by the number of total atoms .

(a) P₄

Molar mass of of the atoms are -

Phosphorous , P = 31 g/mol

Molecular mass of P₄ = ( 4 * 31 ) = 124 g/mol .

(b) H₂O

Molar mass of of the atoms are -

Hydrogen , H = 1 g/mol

oxygen , O = 16 g/mol.

Molecular mass of H₂O = ( 2 * 1 ) + ( 1 * 16 ) = 18 g/mol

(c) Ca(NO₃)₂

Molar mass of of the atoms are -

calcium , Ca = 40 g/mol

nitrogen, N = 14 g/mol

oxygen , O = 16 g/mol.

Molecular mass of Ca(NO₃)₂ = ( 1 * 40 ) + ( 2 * 14 ) + ( 6 * 16 ) = 164 g/mol.

(d)CH₃CO₂H (acetic acid)

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molecular mass of CH₃CO₂H =( 2 * 12 ) + (2 * 16 ) + (4 * 1 ) = 60 g/mol.

(e) C₁₂H₂₂O₁₁ (sucrose, cane sugar).

Molar mass of of the atoms are -

Carbon , C = 12 g/mol.

oxygen , O = 16 g/mol.

Hydrogen , H = 1 g/mol

Molecular mass of C₁₂H₂₂O₁₁ = (12 * 12 ) + ( 22 * 1 ) + ( 11 * 16 ) = 342 g/mol.

4 0

3 years ago

How many molecules in 400g of acetic acid

ki77a [65]

Answer:chemical formula of acetic acid is or

so, molecular mass of acetic acid = 2 × atomic mass of C + 4 × atomic mass of H + 2 × atomic mass of O

= 2 × 12 + 4 × 1 + 2 × 16

= 24 + 4 + 32

= 60g/mol

given mass of acetic acid = 22g

so, no of moles of acetic acid = given mass/molecular mass

= 22/60 ≈ 0.367

so, number of moles of acetic acid is 0.367mol

number of molecules in 0.367 mol of acetic acid = 6.022 × 10²³ × 0.367

= 2.21 × 10²³

Explanation:

3 0

3 years ago

Write the cell notation for the voltaic cell that incorporates each of the following redox reactions:(a) Al(s) + Cr³⁺(aq) → Al³⁺

Sladkaya [172]

The cell notation for the given voltaic cell is as follows

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

<h3>What is a voltaic cell?</h3>

The device in which electrons are transferred through an external source is known as a voltaic cell.

The electron flow of a Voltaic cell allows redox reactions to produce energy in the form of electricity.

It converts the energy of spontaneous redox reaction into electrical energy

An anode, a cathode, and a salt bridge are all parts of a voltaic cell's setup. The salt bridge serves to neutralize the system.

To write the cell notation, identify the oxidation and reduction reactions.

At the anode, oxidation takes place

$Al(s) \longrightarrow Al^{3+} (aq) + 3e^-$

At the cathode, reduction takes place

$Cr^{3+} (aq) + 3e^- \longrightarrow Cr(s)$

While writing cell notation, the anode is written on the left, and the cathode is written on the right

A single vertical line differentiates between the phases and a double vertical line represents the salt bridge.

Now, write the cell notation of the given Voltaic cell

Al(s) | Al³⁺(aq) || Cr³⁺ (aq) | Cr(s)

Learn more about Voltaic cells:

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7 0

2 years ago

A solution is prepared by dissolving 15.0 g of NH3 in 250.0 g of water. The density of the resulting solution is 0.974 g/mL. The

iVinArrow [24]

Answer:

[NH₃] → 3.24 M

Explanation:

Our solute: Ammonia

Our solvent: Water

Solution's mass = Mass of solute + Mass of solvent

Solution's mass = 15 g + 250 g = 265g

We use density to determine, the volume.

D = mass /volume → Volume = m / D → 265 g /0.974 g/mL = 272.07 mL.

We convert the mL to L → 272.07 mL . 1L /1000mL = 0.27207 L

To determine molarity we need the moles of solute in 1 L of solution.

Moles of solute are: 15g / 17g/mol = 0.882 moles

[NH₃] = 0.882mol /0.27207 L → 3.24 M

3 0

3 years ago

How many moles of carbon are in 3.7 moles of c8h11no2

sleet_krkn [62]

Answer:- 29.6 moles of carbon.

Solution:- We have been given with 3.7 moles of $C_8H_11NO_2$ and asked to calculate the moles of C.

Looking at the formula of the compound, there are 8 carbons in it means 1 mol of he compound has 8 moles of C. So, if we multiply the given moles of the compound by 8 then we get the moles of C.

$3.7molC_8H_11NO_2(\frac{8molC}{1molC_8H_11NO_2})$

= 29.6 mol C

Hence. there are 29.6 moles of C in 3.7 moles of $C_8H_11NO_2$ .

8 0

3 years ago