Answer:
Explanation:
<u><em>1. First determine the empirical formula.</em></u>
a) Base: 100 g of compound
mass atomic mass number of moles
g g/mol mol
C 26.06 12.011 26.06/12.011 = 2.17
H 13.13 1.008 13.13/1.008 = 13.03
N 60.81 14.007 60.81/14.007 = 4.34
b) Divide every number of moles by the smallest number: 2.17
mass number of moles proportion
C 2.17/2.17 1
H 13.03/2.17 6
N 4.34/2.17 2
c) Empirical formula
d) Mass of the empirical formula
<u><em>2. Molecular formula</em></u>
Since the mass of one unit of the empirical formula is equal to the molar mass of the compound, the molecular formula is the same as the empirical formula:
Um try B? i think that would be correct. either B or C
Answer:
16.6 km/h
Step-by-step explanation:
Speed = distance/time
= 400.0 m/86.8 s
= 4.608 m/s Convert kilometres to metres
Speed = 4.608m/s × (1 km/1000 m)
= 0.004 608 km/s Convert seconds to hours
Speed = 0.004 608 km/s × (3600 s/1 h)
= 16.6 km/h
umm. what's your question? i'll answer it cause these r just the elements...
Answer:
The concentration of [Ca²⁺] is 8.47 x 10⁻³ M
Explanation:
We consider the solubility of hydroxyapatite,
Ca₁₀(PO₄)₆(OH)₂ ⇔ 10Ca²⁺ + 6PO₄³⁻ + 2 OH⁻
Assumed that there is <em>a</em> mol of hydoxyapatite disolved in water, yielding <em>10a</em> mol Ca²⁺ of and <em>6a</em> mol of PO₄³⁻
We also have Ksp equation,
Ksp = [Ca²⁺]¹⁰ x [PO₄³⁻]⁶ x [OH⁻]² = 2.34 x 10⁻⁵⁹
⇔ 10a¹⁰ x 6a⁶ x (5.30 x 10⁻⁶)² = 2.24 x 10⁻⁵⁹
⇔ 60a¹⁶ = 2.24 x 10⁻⁵⁹ / 5.30 x 10⁻¹²
⇔ a¹⁶ = 0.007 x 10⁻⁴⁷ = 7 x 10⁻⁵⁰
⇔ a = ![\sqrt[16]{7 . 10^{-50} }](https://tex.z-dn.net/?f=%5Csqrt%5B16%5D%7B7%20.%2010%5E%7B-50%7D%20%7D)
= 8.47 x 10⁻⁴
Hence,
[Ca²⁺] = 10<em>a</em> = 8.47 x 10⁻³ M
