Unstable, radioactive atom emits alpha and gamma ray to transform into a stable atom.
Emitting an alpha particle, decreases the mass number by four and atomic number by two.
Emitting gamma ray reduces the excess energy of the radioactive atom.
Answer:
I think that is the literal answer
The given reaction equation for photosynthesis whereby, in the presence of light energy from the Sun and chlorophyll, plants synthesize glucose from carbon dioxide and water. As water is present as a reactant, it doesn’t also appear on the ’products’ side of the equation. So:
Water + carbon dioxide > glucose + oxygen.
As glucose contains 6 carbon atoms, these must be obtained from 6 molecules of CO2. So, overall:
6CO2(g) + 6H2O(l) > C6H12O6(aq) + 6O2(g).
What is photosynthesis?
Photosynthesis is the process plants and other organisms use to convert light energy into chemical energy, which is later released through cellular respiration to power the activity of the organism.
Therefore, This is the equation for photosynthesis whereby, in the presence of light energy from the Sun and chlorophyll, plants synthesize glucose from carbon dioxide and water.
To learn more about photosynthesis refer the given link:-
brainly.com/question/26071939
#SPJ4
Answer:
The electrons are supplied by the species getting oxidized. They move from anode to the cathode in the external circuit. The external battery supplies the electrons. They enter through the cathode and come out through the anode
First, we have to get:
1- The heat required to increase T of ice from -50 to 0 °C:
according to q formula:
q1 = m*C*ΔT
when m is the mass of ice = mol * molar mass
= 1 mol * 18 mol/g
= 18 g
and C is the specific heat capacity of ice = 2.09 J/g-K
and ΔT change in temperature = 0- (-50) = 50°C
by substitution:
∴q1 = 18 g * 2.09 J/g-K *50°C
= 1881 J = 1.881 KJ
2- the heat required to melt this mass of ice is :
q2 = n*ΔHfus
when n is the number of moles of ice = 1 mol
and ΔHfus = 6.01 KJ/mol
by substitution:
q2 = 1 mol * 6.01 KJ/mol
= 6.01 KJ
3- the heat required to increase the water temperature from 0°C to 60 °C is:
q3 = m*C*ΔT
when m is the mass of water = 18 g
C is the specific heat capacity of water = 4.18 J/g-K
ΔT is the change of Temperature of water = 60°C - 0°C = 60°C
by substitution:
∴q3 = 18 g * 4.18 J/g-K * 60°C
= 4514 J = 4.514 KJ
∴the total change of enthalpy = q1+q2+q3
= 1.881 KJ +6.01 KJ + 4.514 KJ
= 12.405 KJ
