Question

A full tub of water weighs 3 1/8 pounds. If the tub is filled up only 1/7 full how much would it weigh?

Answer 1

Answer:

$\frac{25}{56}$ pounds

Step-by-step explanation:

By using unitary method,

∵ 1 full tub of water weighs = $3\frac{1}{8}$ pounds

∴ $\frac{1}{7}$ of a water tub will weigh = $3\frac{1}{8}\times \frac{1}{7}$

                                               = $\frac{(24+1)}{8}\times \frac{1}{7}$

                                               = $\frac{25}{56}$ pounds

Therefore, water filled in $\frac{1}{7}$th part of the tub will weigh $\frac{25}{56}$ pounds.