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Irina-Kira [14]
3 years ago
15

A full tub of water weighs 3 1/8 pounds. If the tub is filled up only 1/7 full how much would it weigh?

Mathematics
1 answer:
Murljashka [212]3 years ago
7 0

Answer:

\frac{25}{56} pounds

Step-by-step explanation:

By using unitary method,

∵ 1 full tub of water weighs = 3\frac{1}{8} pounds

∴ \frac{1}{7} of a water tub will weigh = 3\frac{1}{8}\times \frac{1}{7}

                                               = \frac{(24+1)}{8}\times \frac{1}{7}

                                               = \frac{25}{56} pounds

Therefore, water filled in \frac{1}{7}th part of the tub will weigh \frac{25}{56} pounds.

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