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Rudiy27
3 years ago
10

What is the solution to the system of equations for y= -2x - 4 and y= 2x + 4

Mathematics
2 answers:
MaRussiya [10]3 years ago
4 0
Y = -2x - 4

y = 2x +4

add the two equation

2y = 0 , y =0

2x + 4 = 0

2x = -4

x = -2
nevsk [136]3 years ago
3 0
Y = -2x - 4
y = 2x + 4

substitute the first equation into the second equation to find x;
-2x - 4 = 2x + 4
-4 = 2x + 4 + 2x 
-4 = 4x + 4
-4 - 4 = 4x
-8 = 4x
-2 = x

solve for y given the value of x into the first equation;
y = -2x - 4
y = -2(-2) - 4
y = 0

the answer is; 
x = -2, y = 0     or (-2, 0)

hope this helps, God bless!
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What is the approximate length of the hypotenuse of a right triangle with vertices (-6, 2),
muminat

Answer:

Step-by-step explanation:

A(-6, 2),   B(6,-3) and C(-6, -3)

AB² =  (x₂ - x₁)² + (y₂ - y₁)²

      = ( 6 -[-6])² + ( -3 -2)²

      = ( 6 + 6)² + ( -3 -2)² = 12²  + (-5)²  = 144 + 25 =169

AB = √169 = 13 units

BC²  = ( -6 -6)²  + ( -3 - [-3])² = (-6-6)²  + (-3 +3)²

      = (-12)²  + 0  = 144

BC = √144 = 12 unis

CA²  = (-6 - [-6])²  +(-3-2)²  = (-6 + 6)²  + ( -3-2)²

         = 0 + (-5)²  = 25

CA =√25 = 5 units

length of the hypotenuse of a right triangle  = 13units

4 0
3 years ago
Simplify. write the answer as a fraction. -21/51
Jlenok [28]

Answer:

i think the answer is -7/17

Step-by-step explanation:

hope it help :) i dont really good with fraction

3 0
3 years ago
Can someone help me with this ASAP please I’m being timed !
denpristay [2]

Answer:

The second option (choice b)

Step-by-step explanation:

At -1 is the line starts going up so its increasing. 2 shows that the line is starting to decrease so it would be between -1 and 1 where the line is increasing on the graph.

6 0
3 years ago
A 2-column table with 7 rows. The first column is labeled x with entries negative 3, negative 2, negative 1, 0, 1, 2, 3. The sec
DochEvi [55]

The statements that are true about the intervals of the continuous function are Options 2, 4  and 5

  • f(x) ≤ 0 over the interval [0, 2].
  • f(x) > 0 over the interval (–2, 0).
  • f(x) ≥ 0 over the interval [2, ).

<h3>What is the statement about?</h3>

Looking at the values given, the intervals which satisfies the condition are known to be:

f(x)<=0 over the interval [0,2]

f(x)>0 over the interval (-2,0)

f(x)>=0 over the interval [2,∞)

Because:

Since the table with x  and f(x) values, we have to examine analyze the table and see the each option that is in line with f(x) or not .

Examine the values of x that is from -3 to 3, the f(x) values are both positive and negative . hence f(x)>0 is false over the interval (-∞,3)

Looking at the the interval from 0 to 2, the f(x) values are 0 and negative. Hence, f(x)<=0 over the interval [0,2]

When you look over the interval (-1,1), the f(x) values are said to be both positive and negative and as such, f(x)<0 is false over the interval (-1,1)

When you look at the interval (-2,0) , the f(x)  is positive and as such, f(x)>0 over the interval (-2,0)

Looking at the interval  [2,∞), f(x) is positive and as such, f(x)>=0 over the interval [2,∞)

Therefore, Option 2, 4 and 5 are correct.

Learn more about interval from

brainly.com/question/14454639

#SPJ1

6 0
2 years ago
Find the value of a²+b <br> if...<br> a=-2 and b=5
Nana76 [90]

Answer:

9

Step-by-step explanation:

a²+b

Substituting values,

=> (-2)^2+5

=> 4 + 5

=> 9

4 0
3 years ago
Read 2 more answers
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