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Answer : The mass of aluminium (Al) is 0.413 g
Solution : Given,
Volume of at STP = 513 ml = 0.513 L ( 1 L = 1000 ml )
Molar mass of aluminium = 26.98 g/mole
First we have to calculate the moles of .
At STP,
1 mole occupies 22.4 L volume
now, 0.513 L gives moles of
The moles of = 0.0229 moles
The Net balanced chemical reaction is,
From the balanced chemical reaction, we conclude that
2 moles of Aluminium (Al) produces 3 moles of hydrogen gas
Now the number of moles of aluminium required in 0.0229 moles of hydrogen gas = = 0.0153 moles
Now we have to calculate the mass of aluminium.
Mass of aluminium = number of moles × Molar mass = 0.0153 moles × 26.98 g/mole = 0.413 g
The mass of aluminium required is 0.413 g.