<span>These hydrocarbons are many and this depends on the phase diagram of the substance. In a phase diagram, the phase
can be determined by looking at a certain temperature and pressure. For this case, at a temperature of 20 degrees Celsius and at 1 atmosphere.</span>
Answer:
pH = 12.544
Explanation:
0.0350M 0.0350M 0.0350M.........equilibrium
∴ pOH = - log [OH-]
∴ pH + pOH = 14
⇒ [OH-] = 0.0350 M
⇒ pOH = - Log (0.0350)
⇒ pOH = 1.456
⇒ pH = 14 - 1.456
⇒ pH = 12.544
The precision of a calculated answer is limited by the least precise measurements used in the calculation.
Hope this helps :)
Before we get into the calculation, there are several things that we need to pay attention to:
- There are 6 moles of C
- The carbon mass of a glucose is 180.15 g
So,
<span>#30.5g Glucose(1 mol of glucose/180.15g Glucose)=.169 mol glucose
</span><span>#169 mol glucose(6 Moles of C/1mol C6H12O6) =1.014 mol of C
</span>#<span>1.014 Mol C(6.022x10^23 atoms/ 1 Mol) = 6.11 X 10^23 Atoms of C</span>