Answer:
(x+6)^2+(y-2)^2=65
Step-by-step explanation:
. a. answers vary
b. Yes; the taller the person is, the longer his or her reach.
c. The independent quantities were represented by the x-axis, while the dependent
_quantities were represented using the y-axis.
d. A trend line can generalize the trend in the data.
1-18. a. The graph is in the first quadrant because negative lengths do not exist; the range
of the data determines the kind of graph.
b. Counting by 10’s makes the graph a reasonable size.
c. In this situation, including the origin with the graph is not suggested. It is easier to
see the trend line when the data are not bunched together, and this can be done by
changing the range of the graph to exclude the origin.
d. The graph should include the maximum height (that of Yao Ming) on the x-axis
and the height of the tunnel on the y-axis.
1-21. a. b. c. d.
e. f. g. h.
1-22. a. –8 b. 29 c
Answer:
subtract
Step-by-step explanation:
Answer:
Photomath
Step-by-step explanation:
Answer:
Step 1) Convert the 3.15 percent to a decimal number.
To convert 3.15 percent to a decimal number, you divide 3.15 by 100. In other words, the quotient you get when you divide 3.15% by 100 is the decimal number.
3.15 ÷ 100 = 0.0315
Step 2) Convert the decimal number to a fraction.
To convert the decimal number to a fraction, we make the decimal number the numerator, and 1 the denominator.
0.0315 =
0.0315
1
Step 3) Remove the decimal point in the numerator.
To remove the decimal point in the numerator, multiply both the numerator and denominator by 10000.
0.0315 × 10000
1 × 10000
=
315
10000
Step 4) Simplify the fraction.
The greatest common factor of 315 and 10000 is 5. Therefore, to simplify the fraction, divide the numerator and denominator by 5.
315 ÷ 5
10000 ÷ 5
=
63
2000
Step 5) Convert the fraction to a ratio.
To convert the fraction to a ratio, replace the fraction divider line with a colon.
63
2000
= 63:2000
That was the final step. Below is the answer to 3.15 percent as a ratio.
3.15% = 63:2000
Step-by-step explanation: